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3 years ago

the mass by mass percentage of a solution is 20%. find the mass of the solute dissolved in 500g of solution

Chemistry

1 answer:

GuDViN [60]3 years ago

6 0

Answer:

$m_{solute}=100g$

Explanation:

Hello,

In this case, by considering the mathematical definition of by mass percentage of a solute as shown below:

$\%m/m=\frac{m_{solute}}{m_{solution}}*100\%$

We are able to compute the mass of the solute in a 20% solution having 500 g of solution as follows:

$m_{solute}=\frac{m_{solution}*\%m/m}{100\%} =\frac{500g*20\%}{100\%}\\ \\m_{solute}=100g$

Best regards.

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If 38.5 grams of potassium react with excess oxygen gas, how many grams of potassium oxide can be produced? 4K + O2 yields 2K2O

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Answer:

46.40 g.

Explanation:

It is a stichiometric problem.

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A flask contains 6g hydrogen gas and 64 g oxygen at rtp the partial pressure of hydrogen gas in the flask of the total pressure

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Answer:

B.3/5p

Explanation:

For this question, we have to remember "Dalton's Law of Partial Pressures". This law says that the pressure of the mixture would be equal to the sum of the partial pressure of each gas.

Additionally, we have a proportional relationship between moles and pressure. In other words, more moles indicate more pressure and vice-versa.

$P_i=P_t_o_t_a_l*X_i$

Where:

$P_i$ =Partial pressure

$P_t_o_t_a_l$ =Total pressure

$X_i$ =mole fraction

With this in mind, we can work with the moles of each compound if we want to analyze the pressure. With the molar mass of each compound we can calculate the moles:

moles of hydrogen gas

The molar mass of hydrogen gas ( $H_2$ ) is 2 g/mol, so: