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antiseptic1488 [7]
2 years ago
11

What past or current environments allowed Nuclear Power to form?

Chemistry
1 answer:
Nimfa-mama [501]2 years ago
7 0

Answer:

creation of radioactive wastes such as uranium mill tailings, spent (used) reactor fuel, and other radioactive wastes.

Explanation:

Nuclear energy produces radioactive waste

A major environmental concern related to nuclear power is the creation of radioactive wastes such as uranium mill tailings, spent (used) reactor fuel, and other radioactive wastes. These materials can remain radioactive and dangerous to human health for thousands of years.

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How many moles in Co are there in 6 billion Co atoms
nasty-shy [4]
Hello there!

<span> Use Avogadro's number, 1 mol = 6.02 x 10^23 atoms. 
</span>Convert atoms to moles and you get:

<span>9.97x10^(-15) moles Co
</span>
Hope This Helps You!
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3 years ago
Can somebody please help me ! :(
Helen [10]

Answer:

325

Explanation:

velocity = 3250 Hz x 0.1 m

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Use chemical formulas to write the equation for the reaction between carbon and oxygen
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C(5) + O2(g)


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3 years ago
Which of the following statements about Bohr's model of the atom is true? Bohr's model explains the chemical behavior of all ato
dsp73

I believe the answer is "Bohr's model explains the chemical behavior of all atoms."

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3 years ago
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Consider the reaction 4PH3(g) → P4(g) + 6H2(g) At a particular point during the reaction, molecular hydrogen is being formed at
Svetllana [295]

Answer:

The rate at which P_4 is being produced is 0.0228 M/s.

The rate at which PH_3 is being consumed is 0.0912 M/s.

Explanation:

4PH_3\rightarrow P_4(g)+6H_2(g)

Rate of the reaction : R

R=\frac{-1}{4}\frac{d[PH_3]}{dt}=\frac{1}{6}\frac{d[H_2]}{dt}=\frac{1}{1}\frac{d[P_4]}{dt}

The rate at which hydrogen is being formed = \frac{d[H_2]}{dt}=0.137 M/s

R=\frac{1}{6}\frac{d[H_2]}{dt}

R=\frac{1}{6}\times 0.137 M/s=0.0228 M/s

The rate at which P_4 is being produced:

R=\frac{1}{1}\frac{d[P_4]}{dt}

0.0228 M/s=\frac{1}{1}\frac{d[P_4]}{dt}

The rate at which PH_3 is being consumed :

R=\frac{-1}{4}\frac{d[PH_3]}{dt}

0.0228 M/s\times 4=\frac{-1}{1}\frac{d[PH_3]}{dt}

\frac{-1}{1}\frac{d[PH_3]}{dt}=0.912 M/s

6 0
3 years ago
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