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marishachu [46]
3 years ago
15

Calculate the molarity of a MgSosolution

Chemistry
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

is

Explanation:

because

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How many moles of potassium nitrate, KNO3 are present in a sample with a mass of 85.2 g?
Bingel [31]
0.843 moles would be the answer
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Which is the most likely to be reduced?
NISA [10]

Answer : The correct option is, Zn^{2+}

Explanation :

  • Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. That means, the loss of electrons takes place.

Or we can say that, oxidation reaction occurs when a reactant losses electrons in the reaction.

  • Reduction reaction : It is defined as the reaction in which a substance gains electrons. That means, the gain of electrons takes place.

Or we can say that, reduction reaction occurs when a reactant gains electrons in the reaction.

According to the electrochemical series, Zn^{2+} most likely to be reduced because

Hence, the ion most likely to be reduced is Zn^{2+}.

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3 years ago
Mike mixes two chemicals in a container. The container quickly becomes
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it is an exothermic reaction

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An electrochemical cell is made up of two half-cells connected by a salt bridge and an external conductor. What is the function
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6 0
3 years ago
Read 2 more answers
Calculate the pH in an aqueous 0.120 M nitrous acid solution.
Anvisha [2.4K]

Answer:-  pH is 2.14.

Solution:- Nitrous acid, HNO_2 is a weak acid so first of all we solve for H_3O^+ and then figure out the pH.

the equation is written as:

HNO_2(aq)+H_2O(l)\leftrightharpoons H_3O^+(aq)+NO_2^-(aq)

Initial concentration for the acid is given as 0.120 M. Let's say the change in concentration is x. Then the equilibrium concentrations would be as:

HNO_2=0.120-x

H_3O^+ = x

NO_2^- = x

Ka for nitrous acid is 4.5*10^-^4 and the equilibrium expression for this would be written as:

Ka=\frac{[H_3O^+][NO_2^-]}{HNO_2}

Let's plug in the values in it.

4.5*10^-^4=\frac{(x)^2}{0.120-x}

To make the calculations easy we could ignore x for the bottom and the expression becomes:

4.5*10^-^4=\frac{(x)^2}{0.120}

On cross multiply:

x^2=4.5*10^-^4*0.120

On taking square root to both sides:

x=7.3*10^-^3

So, [H_3O^+]=7.3*10^-^3M

Now we could calculate the pH using the pH formula:

pH=-log[H_3O^+]

pH=-log(7.3*10^-^3)

pH = 2.14

So, the pH of 0.120M nitrous acid is 2.14.

8 0
3 years ago
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