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Aliun [14]
3 years ago
7

What is the product? (X-3)(2x^2-5x+1)

Mathematics
2 answers:
ser-zykov [4K]3 years ago
7 0

Answer:

2x^3-11x^2+16x-3

Step-by-step explanation:

We have been given an expression (x-3)(2x^2-5x+1). We are asked to find the product of our given expression.

Upon using distributive property, we will get:

x(2x^2-5x+1)-3(2x^2-5x+1)

x*2x^2-x*5x+x*1-3*2x^2-3*-5x-3*1

2x^3-5x^2+x-6x^2+15x-3

Upon combining like terms, we will get:

2x^3-5x^2-6x^2+15x+x-3

2x^3-11x^2+16x-3

Therefore, the product of our given expression would be 2x^3-11x^2+16x-3.

ale4655 [162]3 years ago
5 0
Sent you a pic of the product of the expressions.

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A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker
valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is  3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}

#Calculate amount of vinegar used in experiment:

V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml

Hence, the unused vinegar is 2100 ml

8 0
4 years ago
Hello can anyone give me the step by step answer?
NISA [10]

Answer:

C

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 8, - 42 ) and (x₂, y₂ ) = (- 3, - 17 ) ← 2 ordered pairs from the table

m = \frac{-17-(-42)}{-3-(-8)} = \frac{-17+42}{-3+8} = \frac{25}{5} = 5

The line crosses the y- intercept at (0, - 2 ) , then

y = 5x - 2 → C

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3 years ago
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X= 0, 1/2
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Relation

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as 1 has two different values, which is not a function.

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Answer:

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A = ½ (b × h)

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