Answer:
a = ±sqrt(3)
Step-by-step explanation:
a×a×a=a+a+a
Simplifying each side
a^3 = 3a
Divide each side by a
a^3 /a = 3a/a
a^2 = 3
Take the square root of each side
sqrt(a^2) = ±sqrt(3)
a = ±sqrt(3)
Quantity of gasoline needed by a car to run 800 miles = 30 gallons
Quantity of gasoline needed by a car to run 1 mile =
= 30 ÷ 800
= 0.0375 gallons
So , to run 1 mile a car would need = 0.0375 gallons of oil
To run 700 miles the quantity of gasoline needed =
= 700 × 0.0375
= 26.25 gallons of gasoline
Therefore , a car will use 26.25 gallons of gasoline on a trip of 700 miles .
Answer:
it is Zero 0
Step-by-step explanation:
There are two equations and two variables. You can solve for each variable using either the elimination method or the substitution method. Here, I believe the elimination method would be best:
5a = -4b + 5
3a = -2b + 3
You can multiply the second equation by two, so the 4b and -4b in both equations will cancel each other out when you add them. So:
5a = -4b +5
6a = 4b +6
Add both equations together.
11a = 11
a = 1
Plug in the a value into any of the previous equations:
5(1) = -4b + 5
-4b = 0
b = 0
So, since we know that b = 0, 6b is also 0.
Answer:
Exact Form:
−64/5
Decimal Form:
−12.8
Mixed Number Form:
−12 4/5
Step-by-step explanation:
bc I used a calculator
