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2 years ago

10 POINTS!!!!!!!!!!!!

Mathematics

2 answers:

mote1985 [20]2 years ago

8 0

Bigger to smaller I think...

take the smaller length divide by the larger length
1.45/5.8 = 0.25

Verizon [17]2 years ago

5 0

0.25 would be you answer, could you please mark as brainliest??

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Use the relative row frequencies in the table below to answer the question. Movie Preference Action Drama Science- Fiction Comed

Arte-miy333 [17]

No, I would not predict her favorite category is action.

If you look at the percents for the female categories, action is not the highest. The highest category is Comedy. If you have to make a prediction, it would be best to go with Comedy because it is the highest.

4 0

3 years ago

Read 2 more answers

System of Equations y=-x-1 y+x=3 Solve?

ozzi

Solve by substitution

$\sf{y=-x-1}$
$\sf{y+x=3}$

Just plug in y=-x-1 into y+x=3

So we get:

$\sf{(-x-1)+x=3}$

Simplify that:

$\sf{-1=3}$

And since that is not true, that means this system of equations has no solutions!

6 0

2 years ago

Find dy/dx by implicit differentiation for ycos(x)=xcos(y)

alekssr [168]

Answer:

dy/dx = (cos y + y sin x) / (cos x + x sin y)

Step-by-step explanation:

y cos x = x cos y

y (-sin x) + dy/dx cos x = x (-sin y dy/dx) + cos y

-y sin x + dy/dx cos x = -x sin y dy/dx + cos y

dy/dx (cos x + x sin y) = cos y + y sin x

dy/dx = (cos y + y sin x) / (cos x + x sin y)

5 0

2 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

2 years ago

A line, y = mx + b, passes through the point (10, 3) and is parallel to the line 2x+5y=12.

slava [35]

We have been given that a line $y=mx+b$ passes through the point (10, 3) and is parallel to the line $2x+5y=12$ . We are asked to find the y-intercept of the line.