It would be C because it’s asking you to multiple 3/4 by 3/4 sense there is a 2 exponent. And in order to multiply fractions you multiply across the top and bottom and then simplify. Sense c is already simplified that would be your answer. 3 x 3
4x4 9/16 or c
Answer:
the answer is 19-2v combine like terms if not that then try this....
19-2y=0
-2y=-19
Then divide by -2
y=-19/-2
=9.5
They are different equations lol. If you plug in the same x and y for both you wont get the same answer. Do you have answer choices?
Answer:
LCD = 8
Step-by-step explanation:
4/8=4/8
3/4= 6/8
1/2=4/8
Answer:
We conclude that:
![\left(x-8\right)^2+16=x^2-16x+80](https://tex.z-dn.net/?f=%5Cleft%28x-8%5Cright%29%5E2%2B16%3Dx%5E2-16x%2B80)
Step-by-step explanation:
Given the equation
![\left(x-8\right)^2\:+\:16](https://tex.z-dn.net/?f=%5Cleft%28x-8%5Cright%29%5E2%5C%3A%2B%5C%3A16)
First, solve (x - 8)²
Apply Perfect Square formula: (a - b)² = a² - 2ab + b²
![a=x,\:\:b=8](https://tex.z-dn.net/?f=a%3Dx%2C%5C%3A%5C%3Ab%3D8)
![\left(x-8\right)^2=x^2-2x\cdot \:\:8+8^2](https://tex.z-dn.net/?f=%5Cleft%28x-8%5Cright%29%5E2%3Dx%5E2-2x%5Ccdot%20%5C%3A%5C%3A8%2B8%5E2)
![=x^2-16x+64](https://tex.z-dn.net/?f=%3Dx%5E2-16x%2B64)
so the expression becomes
![\left(x-8\right)^2+16=x^2-16x+64+16](https://tex.z-dn.net/?f=%5Cleft%28x-8%5Cright%29%5E2%2B16%3Dx%5E2-16x%2B64%2B16)
Add the numbers: 64+16=80
Therefore, we conclude that:
![\left(x-8\right)^2+16=x^2-16x+80](https://tex.z-dn.net/?f=%5Cleft%28x-8%5Cright%29%5E2%2B16%3Dx%5E2-16x%2B80)