1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IRISSAK [1]
4 years ago
9

Given: < 1 and < 2 are right angles. Prove: < 1 = < 2

Mathematics
1 answer:
sashaice [31]4 years ago
5 0
Statement.
(1). ∠1 is right angle & ∠2 is right angle

(2). ∠1 = ∠2

Reason
(1). Given

(2). Euclid’s Fourth Postulate states that all right angles are equal to one another.

Warning
This is assuming, that we only include Euclidean geometers.
This is because Euclidean geometry only recognise angles between straight lines.

So we have Non-Euclidean geometry for things that are not straight but this raises a question what is a straight line?

A general definition is (A curve is "straight' if tangent vectors stay tangent when parallel-transported along that curve)

Want more info

http://www.physics.ucc.ie/apeer/PY4112/Curvature.pdf

(Elementary Geometry from an Advance Standpoint, by Edwin Moise).

You might be interested in
What is the factored form of the polynomial? x2 − 15x + 36
Lady bird [3.3K]

Answer:

(x - 3)(x - 12)

x would = 3 and 12

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you th
anastassius [24]

Answer:

0.288

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 17.48, \sigma = 3.25, n = 10, s = \frac{3.25}{\sqrt{10}} = 1.027740

Find the probability that the mean printing speed of the sample is greater than 18.06 ppm.

This is 1 subtracted by the pvalue of Z when X = 18.06. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18.06 - 17.48}{1.027740}

Z = 0.56

Z = 0.56 has a pvalue of 0.712

1 - 0.712 = 0.288

The answer is 0.288

7 0
3 years ago
The following list contains the number of movies That a group of 8 students saw in theaters in the past 12 months.
lord [1]

Answer:

I'm pretty sure its 11

first orginize the numbers in numerical order

second the medj an is the middle numbe, if they are to find the mean of those two only

7 0
3 years ago
Read 2 more answers
(2b + 3r) + (4b+ r)
Pavlova-9 [17]
Let's simplify step-by-step. 
<span><span><span><span>2b</span>+<span>3r</span></span>+<span>4b</span></span>+r</span>

Combine Like Terms: 
<span>=<span><span><span><span>2b</span>+<span>3r</span></span>+<span>4b</span></span>+r
</span></span><span>=<span><span>(<span><span>2b</span>+<span>4b</span></span>)</span>+<span>(<span><span>3r</span>+r</span>)
</span></span></span><span>=<span><span>6b</span>+<span>4r</span></span></span>

Answer:<span>=<span><span>6b</span>+<span>4<span>r</span></span></span></span>
4 0
3 years ago
Solve 4 + 4 ( x - 2 ) = 2 ( x + 1 ) - x<br> The question requires you to show your work
kati45 [8]

Answer:

x = 2

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

 (4+(4•(x-2)))-(2•(x+1)-x)  = 0

Step  2  :

Equation at the end of step  2  :

 (4 +  4 • (x - 2)) -  (x + 2)  = 0

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  3x - 6  =   3 • (x - 2)

Equation at the end of step  4  :

 3 • (x - 2)  = 0

Step  5  :

Equations which are never true :

5.1      Solve :    3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

5.2      Solve  :    x-2 = 0

Add  2  to both sides of the equation :

                     x = 2

One solution was found :

                  x = 2

Processing ends successfully

plz mark me as brainliest :)

7 0
4 years ago
Other questions:
  • 10 POINT for 2 SHORT questions,SHORT explanations will do perfectly. also this is for something timed so help asap would be grea
    8·1 answer
  • How many bags have between 22 and 24 candies?
    11·1 answer
  • An electronics store makes a profit of $69 for every standard DVD player sold and $85 for every portable DVD player sold. The ma
    6·1 answer
  • Is .212 greater than .31
    11·2 answers
  • What is the area of the right triangle below?<br> 12<br> 15
    11·2 answers
  • The center of a hyperbola is (−3,2). The length of the conjugate axis is 8 units, and the length of the transverse axis is 12 un
    10·1 answer
  • Solve the equation. If there is no solution, write no solution. Y + 8 – 2(y – 20) &gt; 0
    14·1 answer
  • What’s the answer to this picture/question please give me a simple answer
    13·2 answers
  • Put the equations in slope-intercept form and identify the equations as parallel orperpendicular lines.
    5·1 answer
  • The functions f(x) and g(x) are shown below:
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!