The bearing of point X <u>from</u> point Z is 285°
<h3>Calculating bearings </h3>
From the question, we are to determine the bearing of point X from point Z.
Consider the diagram attached
The bearing of point X <u>from</u> point Z is the measure of the angle from the North of Z in the <u>clockwise direction</u> to the line that goes to X.
That is,
The bearing of point X from point Z = 270° + 15°
The bearing of point X from point Z = 285°
Hence, the bearing of point X from point Z is 285°
Learn more on Calculating bearings here: brainly.com/question/22719608
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Here we can use fact than we can multiply fraction by inverse of fraction instead of dividing it.
Inverse of 1/3 is 3/1
Lets multiply it
- its our result
Answer:
x ≅ 20.10 torr
Step-by-step explanation:
Given that the equation which models blood pH in the question is;
pH(x)=6.1+log(800/x)
where;
pH = 7.7
x = partial pressure of carbon dioxide in arterial blood, measured in torr.
we are asked to find (x)
In order to do that, we use the given equation:
pH(x)=6.1+log(800/x)
since pH = 7.7
7.7 = 6.1 + log (800/x)
7.7 - 6.1 = log (800/x)
1.6 = log (800/x)
x = 20.09509145
x ≅ 20.10 torr
Answer:
Step-by-step explanation:
The given equation is written in the form of y=mx+c (where m is the gradient and c is the y-intercept).
Thus, gradient of given equation= -⅔
The products of the gradient of perpendicular lines is -1.
(Gradient of line)(-⅔)= -1
Gradient of line
Hence, m= 
.
Subst. m= into the equation:
To find the value of c, substitute a pair of coordinates into the equation:
When x= -4, y= 2,
Thus, the equation of the line is .
