Answer:
I mean it would just be q(x) = 0
Step-by-step explanation:
he solution set is
{
x
∣
x
>
1
}
.
Explanation
For each of these inequalities, there will be a set of
x
-values that make them true. For example, it's pretty clear that large values of
x
(like 1,000) work for both, and negative values (like -1,000) will not work for either.
Since we're asked to solve a "this OR that" pair of inequalities, what we'd like to know are all the
x
-values that will work for at least one of them. To do this, we solve both inequalities for
x
, and then overlap the two solution set
Answer:
2 5/6
Step-by-step explanation:
2 2/4 + 1/3
First, you have to make the bottoms of the fraction the same, by figuring out the lowest common denominator. In this case it would be 12. 4x3 = 12. 3x4 = 12.
Multiply the top number by the same number you multiplied the bottom by.
We multiplied the 4 by 3, so we would also multiply the 2 by 3 (which would be 6).
Do the same for the second fraction. 1x4 = 4.
Now we have 2 6/12 + 4/12. We add the top numbers together and we get 10/12.
Now we have to reduce the fractions. We can do this in this situation by just dividing the top and bottom numbers by 2.
2 5/6
For this case we have the following equation:
Let 
We have:
By definition, given an equation of the form 
The quadratic formula, to find the solution can be written as:
In this case we have:
Substituting in the quadratic formula we have:
See attached image
Answer:
Option B
