You have to find the average of 38 and 42 (witch is 40) and then set it to a ratio of 40:100 multiply both sides by 8.5 and we get 340
Answer: The diagram shows a square ABCD with a point inside it which is 1 unit from D, 2 units from A and 3 units from B. Let angle APD= theta . (a) Show that theta = (3pi)/4 (b Show that if P is outside the square , then theta = pi/4 () Is the situation possible if P is 3 units from C instead of from B?
Step-by-step explanation:
Answer:
6.7082
Step-by-step explanation:
Distance Formula=√(x2−x1)^2+(y2−y1)^2
√(-4-2)^2+(6-3)^2
-4 - 2= -6 squared is -36
6-3= 3 squared is 9
add 36 and 9 which = 45
√45 = 6.7082
For the 1 first problem you have to do additive inverse where the subtraction sign is and then combine all the z's and then combine the normal numbers and then put plus sign in between
