Question

If t>0 and t2−25=0, what is the value of t?

Answer 1

Answer:

Final answer is $t=5$.

Step-by-step explanation:

Given equation is $t^2-25=0$.

Now we need to solve that equation for t when $t>0$.

$t^2-25=0$

$t^2-5^2=0$

$(t+5)(t-5)=0$

or $(t+5)=0$, $(t-5)=0$

or $t+5=0$, $t-5=0$

or $t=-5$, $t=5$

Given that t>0

so that means t=-5 is not possible.

Hence final answer is $t=5$.