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3 years ago

Q10. Explain the Retention time, in GC. What will happen to retention time, if you increase the detector temperature

Physics

1 answer:

nadya68 [22]3 years ago

4 0

Answer:

The detector temperature doesn't affect retention time

Explanation:

Retention time is one of the chromatographic parameters. Is defined as the time of a compound spends from injection to detection.

A solute in GC is added to the injector where is volatilized. When volatilized, it pass through a column until the detector.

The detector temperature doesn't affect retention time. To change retention time you must change injector temperature or column temperature. An increase in column or injector temperature results in a decrease in retention time.

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Is cordyceps fungi a predator? If not, what is it?

ASHA 777 [7]

Answer:

It is a predator.

Explanation:

They eat other insects so therefore I think they're a predator.

5 0

3 years ago

When two 10-Ohm resistors are in parallel in a circuit, what is the net resistor value

Elza [17]

Answer:

Net capacitance

let net capacitance be R

1/R = 1/10+1/10

1/R=2/10

1/R=1/5

cross mutiply

R=5

the net capacitance is 5ohms

6 0

4 years ago

A creature moves at a speed of 7.86 furlongs/fortnight (not a very common unit of speed). If 1.0 furlong = 220 yards 1 fortnight

AVprozaik [17]

Answer:

2 0.00130719 m/s

Explanation:

Now we have

7.86 furlongs/fortnight

7.86 x 220 yards / fortnight

1729.2yards / fortnight

1647.8 yards / 14 days

123.5yards / day

123.5 x 0.9144 meter / day

112.meters / day

=112.9meters / 86400s

= 0.001307m/s

5 0

3 years ago

These problems involve Impulse-Mometum theorem, and the Work-Kinetic Energy theorem. Both theorems are combinations of Newton's

ira [324]

a) The time needed to stop the car is 82.5 s

b) The final speed of the bullet is 23,625 m/s

Explanation:

We can solve this part of the problem by using the impulse-momentum theorem, which states that:

"The impulse exerted on an object (the product between force applied and time interval) is equal to the change in momentum of the object"

Mathematically:

$F\Delta t = m\Delta v$

where

F is the force applied

$\Delta t$ is the time interval

m is the mass of the object

$\Delta v$ is the change in velocity

For the train car in this problem, we have

m = 16000 kg is the mass

F = -1900 N is the force applied (with negative sign, since it is applied in the direction opposite to the direction of motion, in order to stop the train)

$\Delta v = 0 -9.8 m/s = -9.8 m/s$ is the change in velocity of the car