Answer:
75 m
Explanation:
The distance x for a uniform acceleration is given by the equation:
The given values are:
a = 6 m/s², t = 5 s, v₀ = 0, x₀ = 0
A man exerts a constant force to pull a 51-kg box across a floor at constant speed. He exerts this force by attaching a rope to
the box and pulling so that the rope makes a constant angle of 36.9∘ above the horizontal. The coefficient of kinetic friction for the box-floor interface is μk = 0.12. What is the work done by the man if he moves the box 10m
1 answer:
Answer:
W=561.41 J
Explanation:
Given that
m = 51 kg
μk = 0.12
θ = 36.9∘
Lets F is the force applied by man
Given that block is moving at constant speed it mans that acceleration is zero.
Horizontal force = F cos θ
Vertical force = F sinθ
Friction force Fr= μk N
N + F sinθ = m g
N = m g - F sinθ
Fr = μk (m g - F sinθ)
For equilibrium
F cos θ = μk (m g - F sinθ)
F ( cos θ +μk sinθ) = μk (m g
Now by putting the values
F ( cos 36.9∘ + 0.12 x sin36.9∘)=0.12 x 51 x 10
F= 70.2 N
We know that Work
W= F cos θ .d
W= 70.2 x cos 36.9∘ x 10
W=561.41 J
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C
Explanation:
why because if something is conserved, it is constant, and does not change with time. A moving body may change its position, acceleration, and velocity with time, but it's energy is constant. The conversation of energy law states that: In any closed system (isolated system) the total energy of the system remain constant.
Mathematically it is written as
Answer:
24 m
Explanation:
The motion of the car is a uniformly accelerated motion (=at constant acceleration), therefore we can find the distance covered by using the following suvat equation:
where
s is the distance covered
u is the initial velocity
t is the time elapsed
a is the acceleration
For the car in this problem:
u = 0, since the car starts from rest
is the acceleration
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Therefore, the distance covered is: