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kaheart [24]
4 years ago
13

If a rock is sitting on a table, the rock exerts a downward force on the table.

Physics
1 answer:
daser333 [38]4 years ago
7 0
This is true. There is a downward force on the table that stabilizes the rock to stay there. 
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On a transverse wave, the crest isa. the highest part of the wave.
Greeley [361]
I think it is C) the resting position of the wave.
3 0
3 years ago
Which statement describes a chemical property related to the particles that make up the material
Stells [14]

Answer: The correct answer would be C.  Salt crystals are hard and brittle because they are made up of atoms that combine by ionic bonding.

Explanation: All the other ones are chemical changes because a new substance is formed.

7 0
3 years ago
What is the critical angle and how does it relate to total internal reflection?
liubo4ka [24]

Answer:

critical angle is the angle of incidence in optically denser medium, for which the angle of reflection in the less denser medium is 90 degree

Explanation:

total internal reflection occurs at one particular angle of incidence where the reflected ray lies on the boundary.

this angle is called the critical angle

6 0
3 years ago
The block in the diagram below is AT REST. However, the tension in the cable is not the only thing holding the block back. Stati
Vedmedyk [2.9K]

Answer:

The  tension in the rope is 229.37 N.

Explanation:

Given:

Mass of the block is, m=33.2\ kg

Coefficient of static friction is, \mu = 0.214

Angle of inclination is, \theta = 31.5°

Draw a free body diagram of the block.

From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.

Forces acting are mg\cos \theta and normal N. Now, there is no motion in the direction perpendicular to the inclined plane. So,

N=mg\cos \theta\\N=(33.2)(9.8)\cos (31.5)\\N=277.415\ N

Consider the direction along the inclined plane.

The forces acting along the plane are mg\sin \theta and frictional force, f, down the plane and tension, T, up the plane.

Now, as the block is at rest, so net force along the plane is also zero.

T=mg\sin \theta+f\\T=mg\sin \theta +\mu N\\T= (33.2)(9.8)(\sin (31.5)+(0.214\times 277.415)\\T= 170+59.37\\T=229.37\ N

Therefore, the  tension in the rope is 229.37 N.

3 0
3 years ago
A load of 500N is carried by 200N effort in a simple machine having load distance 3m Calculate effort distance.​
vlada-n [284]

Answer:

<h2>2.5 m</h2>

Explanation:

Load ( L ) = 500 N

Effort ( E ) = 200 N

Load distance ( LD ) = 3 m

Effort distance ( ED ) = ?

Now, Let's find the Effort distance ( ED )

We know that,

Output work = Input work

i.e L × LD = E × ED

plug the values

500 \times 3 = 200 \times ED

multiply the numbers

1500 = 200 \times ED

Swipe the sides of the equation

200 \: ED \:  = 500

Divide both sides of the equation by 200

\frac{200 \: ED}{200}  =  \frac{500}{200}

Calculate

ED\:  = 2.5 \: m

Hope this helps..

best regards!!

5 0
3 years ago
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