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pickupchik [31]
3 years ago
7

Under favorable conditions bacteria can multiply every 20 minutes. Starting with one bacterial cell, how many bacteria should yo

u expect after 15 hours? Hint: Under favorable conditions, if one bacterium becomes 2 in 20 minutes(1 multiplied by 2), those 2 become 4 in the next 20 minutes, and then those 4 become 8 in the next 20 minutes. That means that 8 bacteria resulted in 1 hour. Now calculate the growth of bacteria for 15 hours.
Physics
1 answer:
Dvinal [7]3 years ago
8 0
120 is the answer .......
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1. The names of the compounds FeS, NaCl, NaOH, and Pb(CN)2 all end in the suffix A. -ite. B. -ic. C. -ide. D. -ate.
shtirl [24]
They all end with suffix "-ide"

In short, Your Answer would be Option C

Hope this helps!
5 0
3 years ago
In class we described the tidal forces that are responsible for raising and lowering thewater level near the shore of the ocean.
Sloan [31]

The newton's law of universal gravitation used to describe how a particle attracts every other particle in the universe.

The equation is given by,

F= G\frac{m_1 m_2}{r_2}

Where,

F= Gravitational force

m_1, m_2 = masses of the objects

r= is the distance between the center of their masses

G= Gravitational constant

For our problem we have defined that,

M_m = 7.24*10^{22}kg (mass of the moon)

d= 3.84*10^8 km (distance Earth-moon)

G= 6.671*10^{-11}Nm^2/kg^2

M=Mass of a person

We have then,

F_m = M\frac{6.67*10^-11*7.34*10^22}{3.84*10^8}

F_m = M*3.320*10^{-5} N

In the other hand we have the force on m-mass due to earth

F_E= MG = M*9.8N

Ratio is given by

\frac{F_m}{F_E} = {M*3.320*10^{-5}}{9.8} = 3.387*10^{-6}

B) Suppose there is a group of young people surfing in the moonlight. They are directly under the moon. At this time the moon exerts its gravitational effect of the earth that causes the tide to rise. Around 6 hours later, when the earth has moved a quarter of the moon, the force on that point decreases, so the tide drops. However, after another 6 hours, people return and experience the same process. In this case the moon is not above them, but on the other side. This is because the moon having an orbit on the earth, generates an external force, similar to the previous one, but the earth reacts in the opposite way. It is like going in a car and turning it, all people will tend to get out of it, because a centrifugal force is experienced.

7 0
4 years ago
If a current of 2.4 a is flowing in a cylindrical wire of diameter 2.0 mm, what is the average current density in this wire?
Gnom [1K]

The average current density in the wire is given by:

J=\frac{I}{A}

where I is the current intensity and A is the cross-sectional area of the wire.


The cross-sectional area of the wire is given by:

A=\pi r^2

where r is the radius of the wire. In this problem, r=\frac{d}{2}=\frac{2.0 mm}{2}=1.0 mm=0.001 m, so the cross-sectional area is

A=\pi (0.001 m)^2=3.14 \cdot 10^{-6} m^2


and the average current density is

J=\frac{I}{A}=\frac{2.4 A}{3.14 \cdot 10^{-6} m^2}=7.64 \cdot 10^5 A/m^2

8 0
3 years ago
Read 2 more answers
A soda has a volume of 560 mL and a density of 3.2 g/mL. What is the mass?
kolbaska11 [484]
The correct answer is: 1792g or 1800g.

(When you round it)
8 0
4 years ago
Help....................​
Nastasia [14]
<h3>Answer:- </h3><h3>16000 </h3><h3> Explanation:-</h3><h3 /><h3>force = 800N</h3><h3>area of 1 feet = 0.025</h3><h3>Area of 2 feet= 0.025+0.025 = 0.050m²</h3><h3>presure = force / area </h3><h3> = 800 N / 0.050</h3><h3> = 16000</h3>

3 0
3 years ago
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