All categories

2 years ago

Can you guys answer these questions please i have allot of work and im trying to do multiple things answer will get brainliest

Mathematics

1 answer:

SpyIntel [72]2 years ago

4 0

Answer:

first one - 30%

second - 15%

third - 40%

fourth - 20%

fifth - 75%

sixth - 70%

seventh - 88%

eighth - 25%

sorry but the last question is too blurry, can you type it and I can help you answer it?

Hope this helps.

You might be interested in

How long will it take Karen to drive 975 miles, if her average speed is 65 miles per hour? Write a formula

irga5000 [103]

It'll take her 15 hours.
Formula: 975= 65x
Where x represents hours

6 0

2 years ago

Read 2 more answers

Which are the center and radius of the circle with equation (x + 5)2 + (y - 4)2 = 9?

alina1380 [7]

Answer:

Center (-5,4) radius 3

Step-by-step explanation:

The standard equation of a circle is

(x-h)^2+(y-k)^2=r^2

where the center is (h,k) and r is the radius

so h=-5 in this case and k is 4

r^2=9 so r=3

4 0

2 years ago

Find the mean of this set of numbers.

Lilit [14]

The answer would C. You must remember for the mean you need to add up all of the numbers, then divide the answer by the number of numbers you have.
Ex:
5,3,7,2,1
All of these numbers added up together is 18.In order to find out the mean, we need to divide the answer(18) by 5 because there are 5 numbers.
Hope this helps!

4 0

2 years ago

“z varies jointly as x and y”

faltersainse [42]

Answer:

urdykdgjjdtdgdmgkgdzkyjt

6 0

2 years ago

Read 2 more answers

Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir

kati45 [8]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}$

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
d=\sqrt{0+1}\implies d=1$

well, the distance from the center to A is 1, namely is "inside the circle".

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}
\\\\\\
d=\sqrt{0+36}\implies d=6$

notice, the distance to B is exactly 6, and you know what that means.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
\\\\\\
\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398$

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.

3 0

2 years ago

Read 2 more answers