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kondaur [170]
3 years ago
7

Q6 Q20.) Solve the equation for x in the interval ​[0,2π).

Mathematics
1 answer:
Marysya12 [62]3 years ago
8 0
Hello there!

See picture below...

Let me know if you have any questions about the answer. As always, it is my pleasure to help students like you!


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In a quiz-based program, there are three teams A, B and C. There is a total of five rounds in a game; 20 marks are given for eac
9966 [12]

From the given scenarios, the positions of winning of each team is; Team C came first, Team A came second and Team B came third

<h3>How to find probability of winning?</h3>

From the question, we can derive the following;

Marks gained by team A = 3 × 20 = 60 marks

Marks deducted = 2 × 10 = 20 marks

Hence;

Total marks for Team A = 60 - 20 = 40 marks

Marks gained by team B = 2 × 20 = 40 marks

Marks deducted = 2 × 10 = 20 marks

Hence, total marks of team B = 40 - 20 = 20 marks

Marks gained by team C = 3 × 20 = 60 marks

Marks deducted = 1 × 10 = 10 marks

Hence,  total marks of team C = 60 - 10 = 50 marks

Thus, we can conclude that;

Team C came first, Team A came second and Team B came third

Read more about Probability of winning at; brainly.com/question/24756209

#SPJ1

7 0
2 years ago
What is the completely factored form of f(x)=x3+5x2+4x−6?
Gre4nikov [31]
f(x)=x^3+5x^2+4x-6
f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)

Synthetic division yields

-3  |  1   5   4   -6
.    |      -3  -6    6
- - - - - - - - - - - - -
.    |  1   2  -2    0

which translates to

\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2

with remainder 0. Now by the quadratic formula,

x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3

and so

f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))
3 0
3 years ago
Find the measures of the four numbered angles
Genrish500 [490]
First, find out x
x+15+2x+15=180
3x+30=180
3x=150
x=50
so the two angels are x+15=65(let's name is ∠5 for convenience), and ∠6= 2x+15=115
notice the two inner lines are marked as congruent, so 
∠4=∠5=65
∠1=180-∠4-∠5=180-65-65=50
Name the right bottom angle ∠7, ∠3=∠7 and ∠3+∠7=the exterior angle 100 degree, therefore, ∠3=50
∠2+∠3=∠4, therefore, ∠2=∠4-∠3=65-50=15
∠1=50, ∠2=15, ∠3=50, ∠4=65
5 0
3 years ago
5x=1/2x does it equal 0 ?
lorasvet [3.4K]

Answer:

Yes it does equal zero.

4 0
3 years ago
Find a cubic function with the given zeros.
Fed [463]

Answer:

The correct option is D) f(x) = x^3 + 2x^2 - 2x - 4 .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x + 4 .

f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 + 2x - 4 .

f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 - 2x^2 - 2x - 4 .

f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0

Now check for other roots as well.

Substitute x=√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0

Substitute x=-√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0

Therefore, the option is correct.

8 0
3 years ago
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