The most likely answer is B.
Highlighting the corresponding parts from the original in the copy is just coloring in the parts of the copy that have the same scale, for example, if the center of the scaled copy is one unit, the original could be 3 units.
        
             
        
        
        
<h3>
Answer: No, this function is not linear</h3>
This function is a hyperbola. It graphs out two disjoint curves. A linear function produces a single straight line graph. All linear functions can be written in the form y = mx+b. The x being in the denominator is one indicator we cannot write the original equation in the form y = mx+b. 
y = 3/x is the same as xy = 3; this tells us every point on y = 3/x has its (x,y) coordinate pair multiply to 3. 
 
        
        
        
Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function 
f(x) =
The two basic hypothesis of the mean valued theorem are 
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function 
 f(x) is continuous in the interval [0,2] as the functions is quadratic and we  can conclude that from its graph
also the f(x) is differentiable in (0,2) 
f'(x) = 6x - 2 
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0 
 6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
    
 
        
             
        
        
        
The range of the function y = x2 is all real numbers, y, such that y ≥ 0.
 
        
             
        
        
        
Answer:
A, If you still need help