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2 years ago

A line passes through the point (5,-11) and has a slope of -2 Find an equation of this line.

Mathematics

1 answer:

Vsevolod [243]2 years ago

5 0

Formula: y = mx + b

m being the slope

Slope given: -2, plug it in

Y = -2x + b

Now find y intercept (b)

Plug in the point (5,-11)

-11 = -2(5) + b

-11 = -10 + b, b = -1

Solution: y = -2x -1

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Step-by-step explanation:

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Step: 2 Now the new dividend is $-x^4+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3$ and remainder will be $x^3+1$

Step: 3 Now the new dividend is $x^3+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2$ and remainder will be $-x^2+1$

Step: 4 Now the new dividend is $-x^2+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x$ and remainder will be $x+1$

Step: 5 Now the new dividend is $x+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x+1$ and remainder will be 0.

Hence When the polynomial $(x^5+1)$ is divided by $(x+1)$ the answer or quotient will be equal to $x^4-x^3+x^2-x+1$ and remainder will be 0.

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Step-by-step explanation:

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