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maw [93]
3 years ago
5

Suppose you have 3 jars with the following contents. Jar 1 has 1 white ball and 4 black balls. Jar 2 has 2 white balls and 1 bla

ck ball. Jar 3 has 2 white balls and 1 black ball. One jar is to be ?selected, and then 1 ball is to be drawn from the selected jar. The probabilities of selecting the? first, second, and third jars are? 1/2?, ?1/3?, and ?1/6 respectively. Find the probability the ball was drawn from Jar 2?, given that the ball is white.
Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

The probability of finding the white ball from second Jar = 20/39

Step-by-step explanation:

Jar 1 contains 1 White ball and 4 black balls

P(w | J₁) = 1/5

Jar 2 contains 2 White balls and 1 black ball

P(w | J₂) = 2/3

Jar 1 contains 2 White balls and 1 black ball

P(w | J₃) = 2/3

Also, Given

P(J₁) = 1/2

P(J₂) = 1/3

P(J₃) = 1/6

P(w) = P(J₁)×P(w | J₁) + P(J₂)×P(w | J₂) + P(J₃)×P(w | J₃)

P(w) = 1/2×1/5 + 1/3×2/3 + 1/6×2/3 =13/30

To find: P(J₂ | w)

According to conditional probability,

P(J₂ | w) = P(J₂)×P(w | J₂)/P(w)

P(J₂ | w) = (1/3×2/3)/(13/30)

P(J₂ | w) = (1/3×2/3)/(13/30) = 20/39

<u>The probability of finding the white ball from second Jar = 20/39</u>

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Answer:

  -13/11

Step-by-step explanation:

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4 0
3 years ago
Use the function below to find F(3). <br><br> F(x) = 4(1/3)^x​
aalyn [17]

Answer:

4/27

Step-by-step explanation:

F(x) = 4(1/3)^x

Let x =3

F(3) = 4(1/3)^3

Exponents first

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Then multiply

f(3) = 4/27

6 0
2 years ago
Read 2 more answers
The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3
viva [34]

Answer:

M_x= 8

M_y = 6

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

M_x = ∑(mass × x-co-ordinate)

M_y = ∑(mass × y-co-ordinate)

Therefore  

M_x = (4×2)+{3×(-3)}+(3×3)

     =8

M_y = {4×(-3)}+{3×1}+(3×5)

    =6

The x co-ordinate of the center of mass is the ratio of M_x to the total mass.

The y co-ordinate of the center of mass is the ratio of M_y to the total mass.

Total mass (m) = m₁+ m₂+ m₃

                        = 4+3+3

                        =10

The x co-ordinate of the center of mass is \frac {8}{10} = \frac {4}{5}

The y co-ordinate of the center of mass is \frac{6}{10}=\frac{3}{5}

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

4 0
3 years ago
Please show me how to work this out
4vir4ik [10]

Answer:

f(x) = -4x + 12

Step-by-step explanation:

y - 2x = -6x + 12

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3 0
3 years ago
Please help asap!!
masya89 [10]
If I were solving this equation, I would put x^2-20x+(100)=(10). Since this is in standard form, you could change this into vertex form by making the equation      y=(x-10)^2 -10.
5 0
3 years ago
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