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Helen [10]
3 years ago
9

Charles has six times as many action figures as ben together the action figures total more than 75 how many does each have

Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer:

We have been given that Charles has six times as many action figures as Ben

Let Ben has x action figures

So according to question Charles will have 6x.

together the action figures total more than 75

x+6x>75

7x>75

x>\frac{75}{7}

So Ben will have more than \frac{75}{7} action pictures.

And 6x>6\frac{75}{7}

6x>\frac{450}{7}

Charles will have more than \frac{450}{7}.

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A bike cost 129.90 what is your total with a tax of 5%
cricket20 [7]

Answer:

so you just use the equation to get the formula and extract the common denominator

Step-by-step explanation:

because i said so

6 0
2 years ago
A rettangle is 10 inches smaller than it is wide. The perimeter of the
meriva

Answer:

A. Width = 25   Length = 15

Step-by-step explanation:

Length = L = Width - 10

Width = W

Perimeter of a rectangle

=> 2 (L + B) = 80

=> 2 (W - 10 + W) = 80

=> 2 (2W - 10) = 80

=> 4W -20 = 80

=> 4W -20 + 20 = 80 + 20

=> 4W = 100

=> 4W/4 = 100/4

=> W = 25

Width = 25

Length = 25 - 10 = 15

So, the answer is A.

6 0
3 years ago
There is a scale model of the White House in Tobu World Square in Japan. The scale used for the model is 1:25. The height of the
Cloud [144]

Answer:

3.4 multiply 1-4

Step-by-step explanation:

there is a scale of white house

3 0
2 years ago
The longer leg of a right triangle is 3 inches more than the length of the shorter leg tripled. the hypotenuse is 3 inches less
lukranit [14]
We have this equation.
A²+B²=C²
We have bits of information that'll help us simplify the equation so there's only one variable.
The longer leg, A, is 3 inches more than the length of the shorter leg, B, tripled.
A=3B+3
Let's plug that in.
(3b+3)²+B²=C²
The hypotenuse, C, is 3 inches less than four times the length of the shorter leg. C=4B-3
Let's plug that in.
(3b+3)²+B²=(4B-3)²
Let's solve.
9B²+18B+9+B²=16B²-24B+9
10B²+18B+9=16b²-24b+9
Let's subtract 9 from both sides.
10b²+18b=16b²-24b
Let's subtract 10b² from both sides.
18b=6b²-24b
Let's add 24b from both sides.
42b=6b²
Let's divide each side by 6.
7b=b²
With this, you can tell that b is 7 since it times 7 equal itself squared.
The shorter leg is 7 inches.
Now, let's look back at the bits of information.
The longer leg of a right triangle is 3 inches more than the length of the shorter side tripled.
3(7)+3=24
So, the longer side is 24. We can either use the other information or plug it into the equation. We can do both. 
The hypotenuse is 3 less than four times the shorter leg.
4(7)-3=25
7²+24²=
49+576=625
√625=25
So, the length of the hypotenuse is 25 inches.
4 0
2 years ago
Max z = 3x1 + 5x2 subject to: 7x1 + 12x2 ≤ 136 3x1 + 5x2 ≤ 36 x1, x2 ≥ 0 and integer find the optimal solution. what is the valu
Reptile [31]
The second constraint is the same as the objective function, so your problem boils down to finding integer solutions to
.. 3x1 +5x2 = 36

There are 3 solutions. They are (x1, x2) = (12, 0), (7, 3), (2, 6)

The value of the objective function there is (obviously) 36.
4 0
3 years ago
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