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Nimfa-mama [501]
3 years ago
15

Michael has 2 meters of yarn. she needs to cut the yarn into 10 equal pieces. how long will each price of yarn be? A.) 20 cm B.)

2cm or C.) 2,000cm​
Mathematics
1 answer:
Karolina [17]3 years ago
3 0
2 meters is equal to 200 centimeters
Divide 200 by 10
200/10 = 20cm

Each piece will be 20 cm long
So your answer is A
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A kite 100 ft above the ground moves horizontally at a speed of 6 ft/s. At what rate is the angle (in radians) between the strin
arlik [135]

Answer:

0.015 radians per second.

Step-by-step explanation:

They tell us that at the moment the speed would be 6 ft / s, that is, dx / dt = 6 and those who ask us is dθ / dt.

Which we can calculate in the following way:

θ = arc sin 100/200 = pi / 6

Then we have the following equation of the attached image:

x / 100 = cot θ

we derive and we are left:

(1/100) * dx / dt = - (csc ^ 2) * θ * dθ / dt

dθ / dt = 0.01 * dx / dt / (- csc ^ 2 θ)

dθ / dt = 0.01 * 6 / (- csc ^ 2 pi / 6)

dθ / dt = 0.06 / (-2) ^ 2

dθ / dt = -0.015

So there is a decreasing at 0.015 radians per second.

3 0
2 years ago
Please help me with this question
gladu [14]
The correct answer choice is (D) 1.10/1 Ib
Hope this helps!
5 0
3 years ago
Abigail jogged 10.6 miles in 2.5 hours. What is her jogging speed in miles per hour? A. 4.32 miles/hour B. 4 miles/hour C. 4.24
Lelechka [254]

do miles/hour =

10.6 miles/2.5 hours =

10.6/2.5 =

4.24 miles/hour


5 0
3 years ago
Read 2 more answers
47,258 redondear el decimal hasta la centésima más próxima ​
KIM [24]

Answer:

I don't speak Spanish

Step-by-step explanation:

4 0
2 years ago
An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n
kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 232 V

Sample mean, \bar{x} = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 232\\H_A: \mu \neq 232

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971

Since,              

|t_{stat}| > |t_{critical}|

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0
2 years ago
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