There are 8 big fish for every 10 small fish, ..... 5 small fish.
log(4) + log(2) - log(5)
= log(2²) + log(2) - log(5)
= 2 log(2) + log(2) - log(5)
= 3 log(2) - log(5)
= log(2³) - log(5)
= log (2³/5)
= log (8/5)
= log (1.6) = 0.2041... (rounded)
15. -2
16. A. The pool was originally empty
Answer:
Step-by-step explanation:
L.C.M. of 2 and 3=6
Raise to the power 6