Given:
U be the set of all books, N the set of all novels, and H be the set of all hardcover books.
To find:
The description for the sets and in words.
Solution:
We have,
U = The set of all books
N = The set of all novels
H = The set of all hardcover books.
We know that means common elements of set N and set H.
Therefore, is set of all books that are both novels and hardcover books.
We know that is the set of elements of universal set except the elements of set H.
Therefore, is the set of all books that are not hardcover books.
a. The table represents a proportional relationship
b. The constant of proportionality is 5/6
<h3 /><h3 /><h3>Proportional relationship:</h3>
Proportional relationship are relationship between variable where their ratios are equivalent. The variables in our case are total weight(pounds) and number of books.
Therefore, let's check if the table represent a proportional relationship.
let
total weight = x
number of book = y
k = constant of proportionality
y = kx
10 = k12
k = 10 / 12 = 5 / 6
y = kx
15 = 18k
k = 15 / 18
k = 5 / 6
y = kx
25 = 30k
k = 25 / 30
k = 5 / 6
y = kx
50 = k60
k = 50/60 = 5 / 6
The constant of proportionality is the same. Therefore, the table represents a proportional relationship
The constant of proportionality(k) is 5/6.
learn more on proportional relationship: brainly.com/question/19543047?referrer=searchResults
Answer:
Mr. Winking 87.9%
Ms. Sand 88.55%
Ms. Sand's class is better
Step-by-step explanation:
Step 1: Average in Mr. Winking's Class 87.9%
Convert each weight factor to a decimal.
Homework 10% = 0.1
Quiz 25% = 0.25
Test 45% = 0.45
Exam 20% = 0.2
Multiply your grades by the weight factors:
Homework 0.1 X 95% = 9.5%
Quiz 0.25 X 85% = 21.25%
Test 0.45 X 87% = 39.15%
Exam 0.2 X 90% = 18%
Add all of these values:
9.5% + 21.25% + 39.15% + 18%
= 87.9%
Step 2: Average in Ms. Sand’s Class 88.55%
Convert each weight factor to a decimal.
Homework 15% = 0.15
Quiz 20% = 0.2
Test 40% = 0.4
Exam 25% = 0.25
Multiply the weight factors by your grades:
Homework 0.15 X 95% = 14.25
Quiz 0.2 X 85% = 17
Test 0.4 X 87% = 34.8
Exam 0.25 X 90% = 22.5
All all these values:
14.25 + 17 + 34.8 + 22.5
= 88.55%
Step 3:
I would rather be in Ms. Sand's class. My average in her class would be 88.55%, whereas in Mr.Winking's Class, my average would be 87.9%. 88.55% is a higher mark than 87.9% and I want higher marks. Therefore, I would get higher marks in Ms. Sand's class.
Answer:
52%
Step-by-step explanation:
40% nuts of 5kg = 40% × 5 = 2kg
56% nuts of 15kg = 56% × 15kg = 8.4kg
total of nuts in mixture = 2 + 8.4 = 10.4kg
10.4kg of nuts in 20kg = 10.4/20 = 52%
The answer is B because the yintercept is -2