The magnetic field at the center of the arc is 4 × 10^(-4) T.
To find the answer, we need to know about the magnetic field due to a circular arc.
<h3>What's the mathematical expression of magnetic field at the center of a circular arc?</h3>
- According to Biot savert's law, magnetic field at the center of a circular arc is
- B=(μ₀ I/4π)× (arc/radius²)
- As arc is given as angle × radius, so
B=( μ₀I/4π)×(angle/radius)
<h3>What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?</h3>
B=(μ₀ I/4π)× (0.9/0.006)
= (10^(-7)× 26.9)× (0.9/0.006)
= 4 × 10^(-4) T
Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.
Learn more about the magnetic field of a circular arc here:
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A. Cause and effect.
Explanation:
An experiment can prove cause and effect in a study unlike observational studies.
- Observational studies is a non-experimental system of investigation.
- It helps to identify the causes(independent variable) and the effect(dependent variables).
- In observational studies, the variables cannot be controlled and so it is difficult to prove the cause and effect.
- An experiment can prove cause and effect because the parameters are tested and can be controlled.
Learn more:
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Explanation:
Work done is given by the product of force and displacement.
Case 1,
1. A boy lifts a 2-newton box 0.8 meters.
W = 2 N × 0.8 m = 1.6 J
2. A boy lifts a 5-newton box 0.8 meters.
W = 5 N × 0.8 m = 4 J
3. A boy lifts a 8-newton box 0.2 meters.
W = 8 N × 0.2 m = 1.6 J
4. A boy lifts a 10-newton box 0.2 meters.
W = 10 N × 0.2 m = 2 J
Out of the four options, in option (2) ''A boy lifts a 5-newton box 0.8 meters'', the work done is 4 J. Hence, the greatest work done is 4 J.
I know I'm a bit late but just in case you still need some of the answers.
1: Oxygen
2: Change in shape
3: Water breaking down into hydrogen and oxygen
4: I think it's Milk but I might be wrong.
I might be wrong about some of them, sorry it's not much.
Answer:
Fusion rates and star evolution increase rapidly because of the conversion of hydrogen molecules to helium.
Explanation:
At the early stage of a star mass, hydrogen atoms are produced. After a few billion years, these hydrogen atoms formed at the core of the star mass begin to fuse on the external side of the core. Hydrogen atoms get rapidly fused, resulting to a contraction of the star core, and as more hydrogen atoms get fused, helium atoms are formed.
This action results into rapid into a rapid and violent burning action of hydrogen atoms around the core.
