Answer:
v₂ = 63.62 m / s
Explanation:
For this exercise in fluid mechanics we will use Bernoulli's equation
P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y₂
where the subscript 1 refers to the inside of the wing and the subscript 2 to the top of the wing.
We will assume that the distance between the two parts is small, so y₁ = y₂
P₁-P₂ = ρ g (v₂² - v₁²)
pressure is defined by
P = F / A
we substitute
ΔF / A = ρ g (v₂² - v₁²)
v₂² = 
suppose that the area of the wing is A = 1 m²
we substitute
v₂² = 
v₂² = 79.10 + 3969
v₂ = √4048.1
v₂ = 63.62 m / s
Answer:
Option A is correct.
The wires will be arranged in order of increasing resistance.
Explanation:
The resistance of a wire is given by
r = (ρl)/A
where r = resistance of the wire
ρ = resistivity of the wire
L = length of the wire
A = cross sectional area of the wire
Provided all the other parameters are constant, resistance is inversely proportional to cross sectional area
r ∝ (1/A)
And the the cross sectional Area of the wire increases with increase in thickness & decreases with thickness
So, decreasing thickness ----> Decreasing Cross sectional Area ----> Increasing resistance.
Answer:True
Explanation: External factors are factors outside of an organisation or an institution that has the capacity of either adversely or positively affect the institution or the Organisation.
For an institution to prosper and perform optimally in an economy.or a country, such Institution must put into cognisance the possible external threats that are capable of affecting it, when Organisations or Institution put strategies in place to control or mitigate such externalities,the institution or Organisation will sure Prosper.
Answer:
Mass is the quantity of matter contained in a body. The mass of an object is measured in kilogram (kg).
Explanation:
