As e is point between df. So we can write df as
df = de + ef
As given df = 78 , de = 5x - 9 , ef = 2x + 10.
So we can write
78 = 5x - 9 + 2x + 10
78 = 7x + 1
On subtracting 1 on booth side
78 - 1 = 7x +1 - 1
77 = 7x
On dividing both side by 7.

11 = x
So x = 11.
So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32
Answer:
32 seconds
Step-by-step explanation:
For some number of seconds (s), Tess's essay length (t) will be ...
t = 42 +1.3s
and Margo's essay length (m) will be ...
m = 122 -1.2s
We will have t > m when ...
t > m
42 +1.3s > 122 -1.2s
2.5s > 80 . . . . . . . . add 1.2s-42
s > 32 . . . . . . . . . . . divide by 2.5
After 32 seconds, Tess's essay will exceed Margo's in length.
4 fiction to 1 nonfiction
(4 x 7 = 28) fiction to (1 x 7 = 7) nonfiction
Therefore, the required ratio is 28 to 7
Answer:
A. subtract s: -7, -10, -13
Step-by-step explanation:
M= -6/5
hope this helped!!