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3 years ago

3 different pairs of numbers that add together to get 1

Mathematics

2 answers:

photoshop1234 [79]3 years ago

8 0

3 different pairs are...
0+1=1
-1+2=1
-2+3=1

max2010maxim [7]3 years ago

3 0

In order to find $3$ different pairs of numbers that adds together to get $1$ you have to follow those steps

we know that

The linear equation that represent this situation is

$x+y=1$

$y=1-x$ ------> equation A

where

x and y are the pair of numbers

Step 1

Assume $3$ different values of x and then with the equation find the values of y

$x1=10\ x2=8\ x3=30$

Step 2

Find the values of y

$y1=1-10=-9$

$y2=1-8=-7$

$y3=1-30=-29$

therefore

the answer is

$10$ and $-9$

$8$ and $-7$

$30$ and $-29$

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3 years ago

A decorator has just painted 400 tiles blue and green at a ratio of 5:20.how many were painted green ? how many were painted blu

zheka24 [161]

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3 years ago

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mars1129 [50]

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7 0

3 years ago

a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream

Nonamiya [84]

the coordinates where the bridges must be built is $(3,-6)$ and $(6,3)$ .

Step-by-step explanation:

Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:

Basically we need to find values of x for which f(x) = g(x) :

⇒ $f(x)-g(x)=0$

⇒ $3x^2- 24x + 39-(3x - 15 ) =0$

⇒ $3x^2- 24x + 39-3x + 15 =0$

⇒ $3x^2- 27x + 54 =0$

⇒ $x^2- 9x + 18 =0$

⇒ $x^2- 6x-3x + 18 =0$

⇒ $x(x- 6)-3(x - 6) =0$

⇒ $(x-3)(x- 6) =0$

⇒ $x=3 , x=6$

Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6

Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3

Therefore , the coordinates where the bridges must be built is $(3,-6)$ and $(6,3)$ .

7 0

3 years ago

Third-degree, with zeros of −3 , − 2 , and 1 , and passes through the point ( 3 , 11 ) .

Masja [62]

Answer:

y = ( x + 3 ) * ( x + 2 ) * ( x - 1 )* 11/60

Step-by-step explanation:

Lets y = f(x) in a cartesian coordinates

Having three zeros:

x = -3 ⇒ x = -2 ⇒ and x = 1

That meas that if x takes the above mentioned values " y " must be zero

therefore y must be of the form

f (x) = y = ( x + 3 ) * ( x + 2 ) * ( x - 1 ) (1)

In that case for y to be zero one of the factors should be zero or

y = 0 x + 3 = 0 and x = - 3 is a zero of the function y .

The same reasoning applies for the other two roots

Now we have to evaluate the other condition.

According to problem statement the function passes through the point ( 3, 11 ) , that means that when x = 3 , y have to be 11, therefore we plug in equation (1) that value to see what happens

y = ( x + 3 ) * ( x + 2 ) * ( x - 1 )

11 = ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1) = 6*5*2 = 60

Then we adjust the expression (1) to meet the condition of the function passing through point ( 3 , 11) as:

y = ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1) * 11/60 (2)

and check to see if we did right

for y to be zero x can be x = - 3 x = -2 and x = 1 in all these cases y = 0. And if x = 3 in equation (2) y = 11. And that what we want to shown. Then the solution is:

y = ( x + 3 ) * ( x + 2 ) * ( x - 1 )* 11/60

8 0

3 years ago