If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
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Answer:
$3.70
Step-by-step explanation:
$25.30 = 2P + 4D. p for popcorn and d for drinks
P= $5.25
$25.30 = 2($5.25) + 4D
$25.30 = $10.50 + 4D
-10.50. -10.50
inverse operations
$14.80 = 4D
÷4. ÷4
Inverse operations
$3.70 = D
For find f(-2) of f(x)=7x+3, plug in -2 for x.
7(-2)+3=y
-14+3=y
y=-11
To find the rate, or the slope, you divide x/y. So 2/6 is 1/3. 3 over 9 is also 1/3. So the rate is 1/3. In rates you always divide, you don't mulitply or subtract or add to find the rate.
The complete question is
<span>Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr and then for another 2 hours and 5 minutes with a constant speed of 12 km/hr what is her average speed for the total trip?</span>
we know that
speed=distance/time
1) Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr
time=2 1/6 hrs----> 13/6 hrs
speed=6 km/h
distance=speed*time----> 6*(13/6)---> 13 km
2)for another 2 hours and 5 minutes with a constant speed of 12 km/hr
time=2hrs+5 minutes----> 2+(5/60)--> 125/60 hrs
speed=12 km/hrs
distance=speed*time----> 12*(125/60)---> 25 km
3) find the average speed for the total trip
total distance=13 km+25 km----> 38 km
total time=(13/6)+(125/60)----> (10*13+125)/60----> 4.25 hours
speed=38/4.25----> 8.94 km/hrs
the answer is
8.94 km/hrs
Using algebra:n+(n+1)+(n+2)+(n+3)+(n+4)=5055n+10=5055n=505-105n=495n=495/5n=99n+1=100n+2=101 answer
