Answer:
Option B. 
Step-by-step explanation:
we know that
The volume of a cone is equal to
we have
substitute
assume
The area of the shaded sector is one-fourth of the area of the whole circle so:
area of shaded region
The area of the shaded region is 9pi units^2
Cos is the adjacent (side next to the angle in question) divided by the hypotenuse (sloped side)
for angle K, this is therefore 7/25
the total no of population=1650
13:17 first add the two numbers 13+17=30
then 13/30×y =715 , i make 13 at the numerator because it's males ratio
after that 30/13×13/30y =715 ×30/13
y =715×30/13
y =1650
after u find the total no it's simple to find the no of females
17/30×1650=935
Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
