The equations for the horizontal and vertical lines passing through the point (6,9) is y = 9 and x = 6 respectively
<u>Solution:</u>
Given, point is (6, 9)
We have to find the equations for horizontal and vertical lines passing through above given point.
Now, let us find horizontal line,
We know that, horizontal line is parallel to x – axis, so slope of our required line is 0.
The point slope form is given as 
Then, line equation in point slope form ⇒ y – 9 = 0(x – 6)
⇒ y – 9 = 0
⇒ y = 9
Now, let us find vertical line,
We know that, vertical line is parallel to y – axis, so slope of our required line is undefined 
Then, line equation in point slope form ⇒ 
⇒ x – 6 = 0(y – 9)
⇒ x – 6 = 0
⇒ x = 6
Hence, the horizontal line equation is y = 9 and vertical line equation is x = 6.
Answer:
9.62 cm²
Step-by-step explanation:
<h2>
Area of sector</h2>
diameter = 7 cm
r = 7 ÷2 = 3.5 cm
Ф = 45°

Area of the given sectors = 2 *4.81
= 9.62 cm²
Original investment is V
In the first year V decreased by 0.08V to give V - 0.08V
In the second year; V - 0.08V increased by $450 to give V - 0.08V + $450
The value (n) after two years = V - 0.08V + $450
The correct choice is 'D.'
Answer:
x=20
Step-by-step explanation:
Look Angle A and D are Congruent so they equal the same
3x−10=2x+10
Subtract 2x from both sides
3x−10−2x=2x+10−2x
x−10=10
Add 10 to both sides.
x−10+10=10+10
x=20
Hope This helps
Answer:
a) CD = 41 m
b) 77.32°
c) 1380 square metres
Step-by-step explanation:
We can divide the trapezium as shown in the diagram below.
a) To find CD, we use Pythagoras Rule:


b) To find <BCD, we use trigonometric function SOHCAHTOA:
sin(BCD) = opp / hyp
sin(BCD) = 40 / 41
sin(BCD) = 0.9756
=> <BCD = 77.32°
c) The area of a trapezium is given as:
A = 1/2 (a + b) * h
where h = height = 40 m
a = top length = 30 m
b = bottom length = 39 m
A = 1/2 * (30 + 39) * 40
A = 1/2 * 69 * 40
A = 1380 square metres