0+0+1+2+3+3+8+9+10=36
36/9
/ = divide
To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=12 and j+k=b=8, so j and k must be 2 and 6
Then the factors are just (a+j)(a+k), in this case:
(a+2)(a+6)
So the missing term was 6
Answer:
F(4) = 97
Step-by-step explanation:
F(x)= x³+2x²+1
when x = 4
F(4)= 4³+2(4²)+1
= 4³+2(4²)+1
= 64 + 2(16) + 1
= 64 + 32 + 1
= 97
