2 years ago

I need help what is the awncer

Mathematics

1 answer:

castortr0y [4]2 years ago

8 0

Answer:

6.44 square meters

Step-by-step explanation:

To solve for area of a rectangle, multiply the length by the width.

$2.3 \times 2.8 = 6.44$

You might be interested in

Select the property of equality used to arrive at the conclusion. If x - 3 = 7, then x = 10

goldenfox [79]

X - 3 = 7
add 3 to both sides
x - 3 + 3 = 7 + 3
x = 10

addition property of equality

4 0

2 years ago

How can you get the variable alone in 84+c=111

VLD [36.1K]

Subtract 84 on the other side of the equal sign and bring down c and the answer you get from 111 - 84.

4 0

3 years ago

Read 2 more answers

Enter the coordinates of the point on the unit circle at the given angle. 135° (-VII, VI Enter

vekshin1

Related angle is 45 degrees, set up a triangle and use exact trig values to solve for x and y, then rationalise the denominators

4 0

2 years ago

Find the value of sin H rounded to the nearest hundredth, if necessary.<br> Help please

Travka [436]

Answer:

sinH ≈ 0.47

Step-by-step explanation:

sinH = $\frac{opposite}{hypotenuse}$ = $\frac{IJ}{HJ}$ = $\frac{16}{34}$ ≈ 0.47 ( to the nearest hundredth )

7 0

2 years ago

You measure 20 turtles' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5

Naily [24]

Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

Step-by-step explanation:

Formula for margin of error : $E=\dfrac{z^*\times (Population\ standard\ deviation)}{\sqrt{Sample\ size}}$

, where z* = Critical z-value.

Given: population standard deviation = 11.5 ounces

Sample size = 20

Z value for 90% confidence level = 1.645

margin of error (E) = $\dfrac{1.645\times11.5}{\sqrt{20}}$

$\approx4.23$

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

3 0

2 years ago