Molecules undergo London dispersion forces:
is the molecule will undergo only London dispersion forces when interacting with other molecules of the same kind.
What are London dispersion forces?
- A sort of force that interacts between atoms and molecules that is often electrically symmetric is referred to as a London dispersion force.
- When viewed from the nucleus, their electron distribution is frequently symmetrical. This dispersion force, which is also known as a transient attractive force, is frequently observed when the locations of the electrons in two nearby atoms cause the atoms to temporarily form dipoles.
- The bond is polar when there are significant variations between the elements' electronegativities; it is nonpolar when there are similarities. When the molecule's dipole moment is equal to O, it is nonpolar; when it differs from O, it is polar.
- The force at these molecules is known as the London dispersion force. In nonpolar molecules, the forces are weak, and partial charges must be induced so that they can bond. In polar molecules, partial charges caused by polarity result in a stronger link known as a dipole-dipole. The dipole-dipole is significantly stronger and known as a hydrogen bond if it is connected to a large electronegative atom (F, O, or N). Ionic force is the name for the attraction force at ionic substances.
- The intermolecular force in the letter an is the London dispersion force because the compound is nonpolar;
<u>Reason for incorrect options:</u>
b: the compound is ionic because Na is a metal and the other part is covalent,
c: two compounds are possible: one is nonpolar and exhibits London dispersion force; the other is polar and exhibits dipole-dipole force; and
d: both compounds exhibit hydrogen bonds (H bonded to O, and H bonded to F).
NOTE: Your question is incomplete, but most probably your full question was, which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind?
A. 
B. 
C. 
D. 
Learn more about the London dispersion forces here,
brainly.com/question/22388709
#SPJ4
Answer:
<span>Increasing concentration, temperature and surface area will increase the yield of products.
Explanation:
Concentration:
Increase in concentration of reactants will increase the number of reactants per unit volume. Therefore, the probability of collisions will increase hence, it will result in the increase in yield.
Temperature:
Increase in temperature increases the kinetic energy of reactants. Therefore, the increase in velocity of reactants results in the collisions with high energy. It makes it feasible for reactants to attain the optimum energy (activation energy) to convert into products with good yield.
Surface Area:
The reactants in grinded / powder form reacts fast as compared to solid form. In fact, grinding results in increase of the surface area of reactants. Greater surface area increases the probability of reactants to colloid. Hence, increases the yield.</span>
Answer:
Copper sulphate is an acidic salt: It is the product of the reaction between a weak copper base and a strong acid , H2SO4
Litmus has a red colour in acidic solutions:
Conclusion: Acidic copper sulphate solution turns blue litmus to red
Baking soda is a basic salt : It is the reaction product of a weak acid , CO2 and a strong base , NaOH
Litmus has a blue colour in basic solutions:
Conclusion: basic baking soda solution turns red litmus to blue
Answer:
When ΔS > ΔH/ T, then the reaction will proceed forward
Explanation:
- The entity that determines the whether a reaction will occur on its own in the forward direction (Spontaneity or Feasibility) is Gibb's free energy.
- Gibb's free energy is the energy available to do work. It is denoted as 'G'. It cannot be easily measured. The change (ΔG) can only be measured. ΔG = ΔH - TΔS
when ΔG is positive, The reaction is not spontaneous (reaction will not occur on its own)
When ΔG is negative, The reaction is spontaneous (reaction will occur on its own)
When ΔG is zero, the reaction is in equilibrium
Option A and E are not correct. ΔH (Enthalpy) cannot determine spontaneity
Option C and D cannot alone determine spontaneity of reaction
For reaction to be spontaneous, TΔS > ΔH
Therefore, ΔS > ΔH/T