White has of the following is true a. The angle of elevation

HELP I NEED HELP FAST. ILL MARK YOU BRAINLIEST.

She plays soccer and golf for a total of 125 minutes:

s + g = 125

She plays soccer 45 minutes more than she plays golf:

s = g + 45 this is for A

B= 40 minutes of golf everyday

C= Yes, because in fact, she plays 85 minutes of soccer everyday, and 85 is greater than 80, so yes she CAN play 80 minutes of soccer every day. Perhaps they meant possible to spend ONLY 80 minutes, then NO, that wouldn't be possible, because then by playing 45 minutes more soccer than golf, she wouldn't have played enough to have 125 total minutes of total play. Technically the way the question is worded, the answer is yes.

I hope this helps!

5 0

2 years ago

The equation of a parabola is given.y=1/8x^2+4x+20 What are the coordinates of the focus of the parabola?

Lena [83]

He equation of a parabola is x = -4(y-1)^2. What is the equation of the directrix?
You may write the equation as 
(y-1)^2 = (1) (x+4) 
(y-k)^2 = 4p(x-h), where (h,k) is the vertex 
4p=1 
p=1/4 
k=1 
h=-4 

The directrix is a vertical line x= h-p 
x = -4-1/4 
x=-17/4 

------------------------------- 
What is the focal length of the parabola with equation y - 4 = 1/8x^2 
(x-0)^2 = 8(y-4) 
The vertex is (0,4) 
4p=8 
p=2 (focal length) -- distance between vertex and the focus 
------------------------------- 
(y-0)^2 = (4/3) (x-7) 
vertex = (7,0) 
4p=4/3 
p=1/3 
focus : (h+p,k) 
(7+1/3, 0)

8 0

3 years ago

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A window shaped like a parallelogram has an area of 23 4/5 square feet. The height of the window is 2 4/5 feet. How long is the

USPshnik [31]

Answer:

base = 8 $\frac{1}{2}ft$

Step-by-step explanation:

The general formula for the area of a parallelogram is:

A = bh, where b = the length of the base and h = the height

Using the given values for area and height, we can solve for the missing variable of 'b':

23 $\frac{4}{5}=\frac{119}{5}$

2 $\frac{4}{5}=\frac{14}{5}$

$\frac{119}{5}=\frac{14}{5}h$

Multiply both sides by the reciprocal:

$(\frac{5}{14})(\frac{119}{5})=(\frac{14}{5})(\frac{5}{14})h$

$\frac{119}{14}=h$

$h=8\frac{1}{2}ft$

5 0

3 years ago

What value should be added to both sides of the equation X2 +12 X +6 equals -5 to solve the question by completing the square

Marta_Voda [28]

X^2 + 12x + 6 = -5
x^2 + 12x = -5 - 6
x^2 + 12x = -11
x^2 + 12x + 36 = -11 + 36.....u add 36 to both sides <=
(x + 6)^2 = 25
x + 6 = (+-) sqrt 25
x + 6 = (+-) 5
x = -6 (+-) 5

x = -6 + 5
x = -1

x = -6 - 5
x = -11

solutions are : x = -1 or x = -11

ur answer : add 36 to both sides.. ur x term is 12, take half of ur x term ,which gives u 6, then u square it, which gives u 36...and add that to both sides

6 0

3 years ago

Last week’s and this week’s low temperatures are shown in the table below.

zavuch27 [327]

Answer:

1st, 2nd, 3rd and 5th statement are correct choices.

Step-by-step explanation:

We have been given a table of low temperatures during last week and this week. We are asked to choose the correct options from our given choices about the center and variability of data.

Low Temperatures of this Week (f): 4, 10, 6, 9 ,6.

Low Temperatures of the last Week (f): 13, 9, 5, 8, 5.

Let us check our given choices one by one.

1. The mean of this week's temperatures is greater than 5 degrees.

$\text{Mean of the low temperatures this week}=\frac{4+10+6+9+6}{5}$

$\text{Mean of the low temperatures this week}=\frac{35}{5}$

$\text{Mean of the low temperatures this week}=7$

Since the mean of this week's temperatures is 7 and 7 is greater than 5, therefore, 1st statement is true.

2. The mean of last week's temperatures is greater than 5 degrees.

$\text{Mean of the low temperatures last week}=\frac{13+9+5+8+5}{5}$

$\text{Mean of the low temperatures last week}=\frac{40}{5}$

$\text{Mean of the low temperatures last week}=8$

Since the mean of last week’s temperatures is 8 and 8 is greater than 5, therefore, 2nd statement is true as well.

3. The range of this week's temperatures is greater than 5 degrees.

We know that range is the difference between greatest value and smallest value of data set.

$\text{Range}=\text{ Greatest value of data set-Lowest value of data set}$

$\text{Range of the low temperature this week}=10-4$

$\text{Range of the low temperature this week}=6$

We can see that range of low temperature this week is 6 and 6 is greater than 5, therefore, 3rd statement is true.

4. The mode of last week's temperatures is greater than 5 degrees.

Mode is the most frequently occurring number found in a set of numbers. We can see that 5 is the mode of last week's temperature and it is not greater than 5, therefore, 4th statement is not true.

5. The range of last week's temperatures is greater than 5 degrees.

$\text{Range of the low temperature last week}=13-5$

$\text{Range of the low temperature last week}=8$

We can see that range of last week's temperatures is 8 and 8 is greater than 5, therefore, 5th statement is a correct choice.

8 0

3 years ago

Read 2 more answers