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3 years ago

What is the GCF of 40 and 48

Mathematics

2 answers:

djyliett [7]3 years ago

7 0

The answer would be 8.

Verizon [17]3 years ago

6 0

40 - 1, 2, 4, 5, 8, 10, 20

48 - 1, 2, 3, 4, 6, 8, 12, 16, 24

The greatest factor they both have is 8, which means that's the answer you're looking for. :)

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For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

PLZ HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!:(

-Dominant- [34]

Sorry for taking so long, it wont let me type a while ago. I have it all fix now hehe. I took a picture of my work, ask me if you still don’t understand.

8 0

3 years ago

Help quickly please!!!

vagabundo [1.1K]

Answer:

1/3 B h

1/3(50.24)(10)

plug in into a calculator

6 0

4 years ago

The equation, y = 12841(1.01)x , represents the average cost of an education at a private college, after 1990. What is the avera

____ [38]

The average cost in 1990 is <span>$12,841.</span>

3 0

4 years ago

Read 2 more answers

At a recreation center, it costs $3 per hour to

Zinaida [17]

It is possible to rent 8 ping pong tables.

This is because if you are renting a bowling lane for 2 hours you would do 12+12 and that’s 24. You would then do 24/3 cause that’s the amount of the cost for 1 hour of the ping pong to rent and that would give you and answer of 8.
Hope that’s helps:)

8 0

3 years ago