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IgorLugansk [536]
3 years ago
15

CHAD HAS 1/2 TON OF GRAVEL TO SPREAD EQUALLY IN 8 SQUARE YARDS FOR HIS DRIVEWAY. HOW MANY TONS OF GRAVEL WILL BE SPREAD IN EACH

SQUARE YARD
Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

1/16

Step-by-step explanation:

½ ton ==> 8 sq. yards

so, each sq. yard needs ½ ÷ 8 = 1/16 ton

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You know the adjacent and you need to find the opposite, so you would use tangent. Your equation would look like this; tan 26°= x/28. You would need to multiply both sides by 28 to simplify it to this; 28*tan 26°= x
Solving this, you would get an answer of 13.7
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olga2289 [7]
For the number before x you would look for the rise over the run. in this case you can see that there is an intersection at (-2,0) and (0,1) you find the difference ox each so you have 2/1 or just 2 you can tell that the line is going up so it is positive. for the addition part look at where the y intercept is in this case it is at positive one. this makes your equation y=2x+1
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Can u solve the answer
pickupchik [31]

Answer:

She needs 50 ft² of wood to cover the table

Step-by-step explanation:

You need to know the formula for area of a trapezoid, which is

A = (B1 + B2)h/s     (add the bases together, multiply by the height, then divide

                                by 2)

We are given B1 = 12, B2 = 8, and h = 5, so plug them in and simplify

A = (12 + 8)(5)/2

 

    A = (20)(5)/2

       A = 100/2

         A = 50 ft²

5 0
3 years ago
Jason is training to run a marathon. His goal for this week is to run a minimum of 42 miles. So far this week, he has already ru
ivanzaharov [21]

Answer:

6m + 18 ≥ 42

Step-by-step explanation:

6m + 18 ≥ 42

------

3 0
2 years ago
A survey found that​ women's heights are normally distributed with mean 63.3 in. and standard deviation 2.7 in. The survey also
mylen [45]

Answer:

A) There is a 100% chance of meeting the height requirement for women.

B) There is a 99.89% chance of meeting the height requirement for men.

C) New height requirements are:

71.9 inches for men and 58.9 inches minimum for women.

At least 58.9 inches and at most 71.9 inches.

Step-by-step explanation:

This question involves finding z values which tell us the percentage from 0 to x.

z = (x-μ)/σ

A) In this question, the minimum sample point is 4 ft 9 inches or converting to inches, we have;(4*12) + 9 =57 inches.

The maximum sample point is 6 ft 4 inches which in inches gives; (6*12) + 4 = 76 inches

For the minimum point;

z = (57 - 63.3)/2.7 = -2.33

From the z-distribution table, this equates to 0.0099.

The maximum;

z = (76 - 63.3)/2.7 = 4.70

From the z-table, it gives 0.999.. Basically 100%.

So there is a 100% chance of meeting the height requirement for women.

B) For men;

the minimum z = (57 - 67.3)/2.8 = -3.68 which gives 0.00012 from the z-distribution table.

The maximum;

z = (76 - 67.3)/2.8 = 3.07 which gives 0.9989 from the z-distribution table. Basically, 99.89%.

So there is a 99.89% chance of meeting the height requirement for men.

C) To exclude the tallest 5% of men, we need to find the z-value for 0.95 and then solve for x.

Thus from the z-table, z = 1.65. So;

1.645 = (x - 67.3)/2.8

4.606 = x - 67.3

x = 67.3 + 4.606

x ≈ 71.9 inches for men.

So, Current minimum is okay.

To exclude the shortest 5% of women, we need to find the z for 0.05.

From the z-distribution table, it has a value of -1.645. So;

-1.645 = (x - 63.3)/2.7

-4.4415 = x - 63.3

x = 63.3 - 4.4415

x ≈ 58.9 inches minimum.

So, Current maximum is okay.

5 0
3 years ago
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