Answer:
<em>The answer is Hence Proved</em>
Step-by-step explanation:
Given that CB║ED , CB ≅ ED
To prove Δ CBF ≅ Δ EDF
This means that the length of CB is equal to ED
As CB║ED The following conditions satisfies when a transversal cut
two parallel lines
- ∠ EDF = ∠ FBC ( Alternate interior points )
- ∠ DEF = ∠ FCB ( Alternate interior points )
∴ Δ CBF ≅ Δ EDF ( By ASA criterion)
The Δ CBF is congruent to Δ EDF By ASA criterion .
<em> Hence proved </em>
P(both work) = ((10-3)/10)*((10-3-1)/9) = (7/10)*(6/9) = 42/90
<span>P(at least one does not work) = 1 - P(both work) = 1 - 42/90 = 48/90 = 24/45.</span>
Answer:
d + c = 12
d = 2c − 3
Step-by-step explanation:
Youre welcome ma boi
<u>Answer</u>:
The discriminant of 3 x squared minus 10 x = negative 2 is 76
<u>Explanation</u>:
<u>Given</u>:

..........(1)
We can find out the discriminant by using the formula

So from the equation (1)
We have b = -10
a= 3
c= 2
Now put all these values of a,b and c in the formula of discriminant to find out the value of D
So


D=76
So the discriminant of the given quadritic equation = 76