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3 years ago

In ΔOPQ, the measure of ∠Q=90°, PO = 97, OQ = 65, and QP = 72. What is the value of the tangent of ∠O to the nearest hundredth?

Mathematics

1 answer:

garri49 [273]3 years ago

3 0

Answer: 1.11

Step-by-step explanation:

with tangent I guess A+B=C, B goes over A. But like I bet you're wondering how will yk which is a or b? idk either, but I tried my luck and got it right. So yk how C (hypotenuse) is always the biggest number? Well whichever number is bigger (A or B) the bigger number will go over the smaller one and then you round it to the nearest hundredth. I'm not good at rounding, so I used Math//way to get it for me. So it could be like , 12+36=40 (just picking random numbers), 36 will go over 12. And then you round it. I hope thus makes sense, it's 5:40AM rn. I should be sleep because I have a job interview at 3PM today.

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Which postulate or theorem justifies this statement: ∠ 11 + ∠ 10 = 180°

Trava [24]

Answer:

Same-side Interior Angles theorem justifies ∠ 11 + ∠ 10 =180°

Step-by-step explanation:

To Prove:

∠ 11 + ∠ 10 =180°

Proof:

Consider lines are Parallel,then

Corresponding Angles are Equal

∴ ∠ 10 = ∠ 12 say (equation 1)

Now by Linear Pair postulate we have,

∴ ∠ 11 + ∠ 12 = 180° say (equation 2)

Now by replacing ∠12 by ∠ 10 from equation 1 in equation 2 we get

∴ ∠ 11 + ∠ 10 = 180°

Hence proved the above statement.

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3 years ago

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Tomtit [17]

Answer:

The 3rd one should be right

Step-by-step explanation:

I hope that helps

7 0

3 years ago

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Luba_88 [7]

Answer:

As shown in picture,

Option 2 is correct.

Horizontal asymptote at y = 0 (graph approaches to 0 when x at -infinity and + infinity)

Option 4 is correct.

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Option 5 is correct.

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6 0

3 years ago

Read 2 more answers

Mckinney donated 9 soda bottles to the after

Papessa [141]

Answer:

33%

Step-by-step explanation:

9 - 6 = 3

3 / 9 = 0.33

0.33 x 100 = 33%

Amount of what you have divided by the total amount of something, times by 100 gives you the percentage

4 0

3 years ago

Read 2 more answers

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago