A company publishes statistics concerning car quality. The initial quality score measures the number of problems per new car sold. For one year, Car A had 1.26 problems per car. Let the random variable X be equal to the number of problems with a newly purchased model A car. Complete (a) and (b) below.
a. If you purchased a model A car, what is the probability that the new car will have zero problems? The probability that the new model A car will have zero problems is :___ (Round to four decimal places as needed.)
b. If you purchased a model A car, what is the probability that the new car will have two or fewer problems? The probability that a new model A car will have two or fewer problems is :___ (Round to four decimal places as needed.)
Hope this helps you find your answer
The equation which relates the change in price per sticker purchased is y = 2.05x
- The number of stickers purchased = 10
The change in price per sticker purchased can be expressed as :
- Price change / number of stickers
- Change in price per sticker = $20.50 / 10
- Change in price per sticker purchased = 2.05
Therefore, the required equation which related y and x is :
y = 2.05x
Learn more :brainly.com/question/13218948
To take a percent, move the decimal point of the percent two places to the left. 7% = 0.07
Then multiply:
12.60 • 0.07 = 0.88
12.60 + 0.88 = 13.48
The total cost is: $13.48
Hello,
Please, see the attached file.
Thanks.
Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)
