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DiKsa [7]
3 years ago
11

HELP ASAP I give brainliest!

Mathematics
1 answer:
Bingel [31]3 years ago
8 0
1. 5%

2. That’s the only answer I have, sorry.
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A password is 4 characters long and must consist of 3 letters and 1 of 10 special characters. If letters can be repeated and the
Ne4ueva [31]

The number of possibilities for constructing the 4 characters long password with specified conditions is given by: Option C: 703,040

<h3>What is the rule of product in combinatorics?</h3>

If a work A can be done in p ways, and another work B can be done in q ways, then both A and B can be done in p \times q ways.

Remember that this count doesn't differentiate between order of doing A first or B first then doing other work after the first work.

Thus, doing A then B is considered same as doing B then A

We're specified that:

  • The password needs to be 4 characters long
  • It must have 3 letters and 1 of 10 special characters.
  • Repetition is allowed.

So, each of 3 characters get 26 ways of being 1 letter. (assuming no difference is there between upper case letter and lower case letter).

And that 1 remaining character get 10 ways of being a special character.

So, by product rule, this choice (without ordering) can be done in:

26 \times 26 \times 26 \times 10 = 175760 ways.

Now, the password may look like one of those:

  1. L, L, L, S
  2. L, L, S, L
  3. L, S, L, L
  4. S, L, L, L

where S shows presence of special character and L shows presence of letter.

Those 175760 ways are available for each of those four ways.

Thus, resultant number of ways this can be done is:

175760 \times 4 = 703040

Thus, the number of possibilities for constructing the 4 characters long password with specified conditions is given by: Option C: 703,040

Learn more about rule of product here:

brainly.com/question/2763785

5 0
2 years ago
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