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almond37 [142]
2 years ago
15

Determine if true: 10x3-20=20

Mathematics
2 answers:
Anastasy [175]2 years ago
7 0

Answer: This equation is <u>FALSE. </u> The left side 10 does not equal to the right side which is 20.

Step-by-step explanation:

nexus9112 [7]2 years ago
4 0

Answer:

False

Step-by-step explanation:

10x3=30

30-20=10

10=20

These equations dont match.

Hence, the equation is false

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Employee B got a one time bonus of $90. He makes $13 an hour. If he was paid $415, how
Marina CMI [18]

Answer:

y=mx+b format... 8th grade math class memories...ahhh

Step-by-step explanation:

Employee B-

one time bonus of 90 gets plugged into the b spot

13 an hour goes into the m space

415 total paid goes into the y spot

415=13(x)+90

subtract 90 from 415 and 90

325=13(x)

divide 325 by 13 and 13

25=(x)

Now plug x into the y=mx+b format with all your other numbers to check

y=13(25)+90

y=415!!

Hope this wasn't too confusing, good luck!

3 0
3 years ago
For each babysitting job, Tamar charges $6 for bus fare plus $8 per hour. She only accepts babysitting jobs if the total charge
gregori [183]

Answer:

B. 3 hours

Step-by-step explanation:

It’s 6+8x=30

8 0
3 years ago
Read 2 more answers
The measure of angle 4 is 120°, and the measure of angle 2 is 35°. What is the measure of angle 5?
pickupchik [31]

If this was a triangle, the answer would be 35 degrees. Can you plz show a graph if you have one though?

8 0
3 years ago
Read 2 more answers
The average weight of a newborn panda is 0.2, or 2/10 pound. Between what two integers is the weight of a newborn panda?​
sweet-ann [11.9K]

Answer:

\frac{2}{10} lies between 0 and 1.

Step-by-step explanation:

We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:

n < \frac{a}{b} < n +1, n, a, b \in \mathbb{N}_{O}

\mathbb{N}_{O} = \mathbb{N}\,\cup\,{\{0\}}

Which is now developed mathematically to deduce a useful expression to find integers:

1) n < \frac{a}{b} < n +1 Given

2) n \cdot 1 < \frac{a}{b} < n\cdot 1 + 1 Modulative property

3) n \cdot (b\cdot b^{-1}) < a\cdot b^{-1} < n \cdot (b\cdot b^{-1}) + b\cdot b^{-1} Existence of Multiplicative inverse/Definition of division.

4) (n\cdot b)\cdot b^{-1} < a\cdot b^{-1}< [(n+1)\cdot b] \cdot b^{-1} Commutative, Associative and Distributive properties.

5) n\cdot b < a < (n+1)\cdot b Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.

If we know that a = 2 and b = 10, the following inequation is formed:

10\cdot n < 2 < 10\cdot (n+1)

It is quite evident to conclude that \frac{2}{10} lies between 0 and 1.

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3 years ago
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