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Masja [62]
3 years ago
8

Jika f(x) = 8x p dan f(p) = -54,nilai p

Mathematics
1 answer:
enyata [817]3 years ago
7 0
I hope this helps you

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A roulette wheel has the numbers 1 through 36, 0, and 00. A bet on five numbers pays 6 to 1 (that is, if one of the five numbers
tatiyna

Answer:

5 cents

Step-by-step explanation:

So the roulette wheel would have a total of 38 numbers, which means 38 different possible cases. Since you are allowed to bet on 5 numbers, the chance to win this is 5 out of 38 and to lose this is 33 out of 38.

If you win, you get 1 + 6 = 7 dollar, and if you lose, you lose 1 dollar.

Therefore the expected amount out of this game is:

E = 7\frac{5}{38} - 1\frac{33}{38} = \frac{35}{38} - \frac{33}{38} = \frac{2}{38} = \frac{1}{19} = \$0.0526

or 5 cents

7 0
3 years ago
Suppose the sales tax rate is 5% on a $1300 tv how much is is the amount of tax?
shepuryov [24]

Answer:

Therefore, amount of tax is $65.

Step-by-step explanation:

Amount of tax = Tax% of $1300

Amount of tax = 5% of $1300

= (5/100) of $1300

= (1/20) of $1300

= $130/2

= $65

3 0
3 years ago
PLZ HELP<br><br> cot2x + 4cscx - 20
tamaranim1 [39]

Answer:this is not an equation

Step-by-step explanation:

3 0
3 years ago
Find g(2/3). Simplify your answer. Type an exact answer, using radicals as needed).
ki77a [65]
The solution is 2sqrt77/77.  You just fill in 2/3 for the x's. When you do that, you do that you get (2/3)/sqrt(9-[2/3]^2) which, simplified, is (2/3)/sqrt(9-[4/9]). Now use the common denominator under the radical of 9 to get (2/3)/sqrt([81-4]\9).  Simplifying even further gives you (2/3)/([sqrt(77)]/3). Now do that division by multiplying 2/3 by the reciprocal of ([sqrt(77)]/3) to get 2/sqrt77.  I rationalized the denominator to get that result up there.
5 0
3 years ago
Determine the zeros of the function f(x) = 3x^2 -7x+1
IceJOKER [234]
I will use the quadratic formula.

\text{The zeros of function:}\ f(x)=0\\\\f(x)=3x^2-7\\\\f(x)=0\to3x^2-7x+1=0\\\\a=3;\ b=-7;\ c=1\\\\b^2-4ac=(-7)^2-4\cdot3\cdot1=49-12=37\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-(-7)-\sqrt{37}}{2\cdot3}=\dfrac{7-\sqrt{37}}{6}\\\\x_2=\dfrac{-(-7)+\sqrt{37}}{2\cdot3}=\dfrac{7+\sqrt{37}}{6}

6 0
3 years ago
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