Word | know | Unknown
Language| 12 | x
Total | 180 | 28980
Use cross multiply:
12(28980) = 180(x)
347760 = 180x
347760/180=1932
Answer:
Both equation represent functions
Step-by-step explanation:
The function is the relation that for each input, there is only one output.
A. Consider the equation

This equation represents the function, because for each input value x, there is exactly one output value y.
To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.
When you intersect the graph of the function
with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.
B. Consider the equation

This equation represents the function, because for each input value x, there is exactly one output value y.
When you intersect the graph of the function
with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.



with that template in mind,

C = 2 B = 1 C/B = 2/1 or +2, horizontal left shift of 2 units
f(x) shifted left by 2 units is f(x+2).
Answer:
11
Step-by-step explanation:
Simplify both sides of the equation.
Subtract 15 from both sides.
Divide both sides by -2.
x = 11
Plz send pic for me to do this