Question

Suppose you had to

Answer 1

Answer:

For 0 correct answer $^4c_0p^0q^{4-0}$

For 1 correct answer $^4c_1p^1q^{4-1}$

For 2 correct answer $^4c_2p^0q^{4-2}$

For 3 correct answer $^4c_3p^1q^{4-3}$

For 4 correct answer $^4c_4p^1q^{4-4}$

Step-by-step explanation:

It is given that there are 4 questions n = 4

Number of choices is 4

So probability of getting correct answer $=\frac{1}{4}$

Probability of getting incorrect answer $=1-\frac{1}{4}=\frac{3}{4}$

Probability distribution is given by $^nc_rp^rq^{n-r}$

Therefore probability distribution of 0 correct answer

$^4c_0p^0q^{4-0}$

Therefore probability distribution of 1 correct answer

$^4c_1p^1q^{4-1}$

Therefore probability distribution of 2 correct answer

$^4c_2p^0q^{4-2}$

Therefore probability distribution of 3 correct answer.

$^4c_3p^1q^{4-3}$

Therefore probability distribution of 4 correct answer.

$^4c_4p^1q^{4-4}$