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nikdorinn [45]
2 years ago
11

If the probability of being a great ape is 0.01 and the probability of having orange hair is 0.2, and having orange hair and bei

ng a great ape are independent, what is the total probability of an orange-haired great ape
Mathematics
1 answer:
MariettaO [177]2 years ago
6 0

Answer:

0.002 = 0.2% total probability of an orange-haired great ape

Step-by-step explanation:

We have these following probabilities:

1% = 0.01 probability of being a great ape.

20% = 0.2 probability of having orange hair.

What is the total probability of an orange-haired great ape

They are independent, so we just multiply these probabilities.

0.01*0.2 = 0.002

0.002 = 0.2% total probability of an orange-haired great ape

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A circle has a radius if 20 centimeters and a central angle that measures 118 degrees. Find the length of the arc defined by thu
babymother [125]

\textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=20\\ \theta =118 \end{cases}\implies \begin{array}{llll} s=\cfrac{(118)\pi (20)}{180}\implies s=\cfrac{118\pi }{9} \\\\\\ s\approx 41.19~cm \end{array}

4 0
1 year ago
What is the area of the shaded region of the circle?
eduard

Answer:

12π ft², B

Step-by-step explanation:

Area of circle: radius²π

The area of the entire circle would thus be 6²π, or 36π

Note that a circle has a total degree measure of 360°, and the shaded area is 120°. Thus, the area of the shaded region would be 120/360 of the circle's area, or 1/3.

1/3 * total area of the circle = area of the shaded region

1/3 * 36π = 12π

Thus, the answer is 12π ft², or B.

6 0
3 years ago
The histogram shows the distribution of hurricanes that have hit a country from 1851 through 2015, where 1 is the weakest level
aleksandrvk [35]

Answer:

a) mean = 0.2

variance = 0.0391

standard deviation = 0.198

b) The average hurricane is aprox. category 2.*  (B)

Step-by-step explanation:

In order to find the mean, variance, and standard deviation, let us for a table for the data:

level            x

1             0.411

2            0.278

3            0.221

4            0.080

5            0.010

Calculating the mean (\bar{x})

\bar{x} = \frac{x_1+x_2+x_3+x_4 + x_5}{n}\\\\\bar{x} = \frac{0.411 + 0.278 + 0.221 + 0.080 + 0.010}{5}\\\bar{x} = \frac{1}{5}\\ \bar{x}  = 0.2

∴Mean = 0.2

level            x         x- \bar{x}         (x - \bar{x})^2  

1             0.411         0.211         0.0445  

2            0.278       0.078        0.0608

3            0.221        0.021         0.000441    

4            0.080        -0.12         0.0144

5            0.010         -0.19         0.0361

                                              \sum(x - \bar{x})^2 = 0.1562

variance = \frac{\sum(x - \bar{x})^2}{n-1} \\variance = \frac{0.1562}{4} \\variance = 0.0391

standard deviation = √(variance)

Standard deviation = √(0.0391)

Standard deviation = 0.198

b) the average hurricane is aprox.  category 2 (B)

8 0
3 years ago
2) Robert is trying to raise money for the children. Last year Robert raised $85. While this year he raised $125. By what percen
bekas [8.4K]

Answer:

5×^4

Step-by-step explanation:

I think that is the answer.

5 0
3 years ago
Can yall help me? L.O.L<br> 2+2=1<br> 1+1=1<br> 5+5=8<br> 0+0=10
valentinak56 [21]

Answer:

2+2=4

1+1=2

5+5=10

0+0=0

lol this was soooo hard lol

6 0
3 years ago
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