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Lapatulllka [165]
4 years ago
9

A certain type of flashlight requires two type-D batteries, and the flashlight will work only if both its batteries have accepta

ble voltages. Suppose that 80% of all batteries from a certain supplier have acceptable voltages. Among fifteen randomly selected flashlights, what is the probability that at least fourteen will work? (Round your answer to three decimal places.)
Mathematics
1 answer:
VikaD [51]4 years ago
4 0

Answer: Our required probability is 0.167.

Step-by-step explanation:

Since we have given that

n = 15

Probability of success p = 80% = 0.8

Probability of failure q = 20% = 0.2

We need to find the probability that at least fourteen will work.

So, by Binomial distribution, we get that

P(X\geq 14)=P(X=14)+P(X=15)\\\\P(X\geq 14)=^{15}C_{14}(0.8)^{14}(0.2)+^{15}C_{15}(0.8)^{15}\\\\P(X\geq 14)=0.167

Hence, our required probability is 0.167.

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Correct option is A) [-13/4, 9/4] .

<u>Step-by-step explanation:</u>

Here we have following equation as  |2 + 4x| = 11 or , |2 + 4x| = 11 . We need to solve for the value of x .Let's find out:

We know that Modulus Function is both positive & negative for particular values of x , i.e.

|2 + 4x| is positive :

⇒ |2+4x|=11

⇒  2+4x=11

⇒  4x=9

⇒  x = \frac{9}{4}

|2 + 4x| is negative :

⇒ |2+4x|=11

⇒  -2-4x=11

⇒  -4x=13

⇒  x = \frac{-13}{4}

Therefore , Correct option is A) [-13/4, 9/4] .

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