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agasfer [191]
3 years ago
12

 First CORRECT answer gets brainliest!

Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0
Https://www.illustrativemathematics.org/content-standards/tasks/703  check it out it might help
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Solve −6x+6−7=2x+8 for x. How would I solve this?
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Step-by-step explanation:

−6x+6−7=2x+8

-1-8=2x+6x

8x=-9

x= -\frac{9}{8}

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X -5x -14=0 quadratic formula
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No its a negitive number one x minus five x's equal -14
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Tell me which statements belong in "agree" and disagree".
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4 0
2 years ago
A bicycle lock has a four-digit code. The possible digits, 0 through 9, cannot be repeated. What is the probability that the loc
kozerog [31]
First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities
the second digit is any of the remaining 9, after having picked one. 
and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=\frac{n(first -digit- is- 5)}{n(all-codes)}= \frac{1*9*8*7 }{10*9*8*7 }= \frac{1}{10}=0.1

b. <span>What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6</span>
4 0
3 years ago
Read 2 more answers
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