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IRINA_888 [86]
3 years ago
10

Your promotional budget for the year is $300 for personal selling, $300 for sales promotion, \$1,500 for advertising, and $500 f

or image promotion. What is your total promotional budget for this year?
a) $2,000

b) $2,600

c) $3,600

d) $4,600
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

to get the total promotion budget for the year we will add $300 for personal selling plus $300 for sales promotion plus $1500 for advertising plus $500 for image promotion to the a total of 2600 dollars

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When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
£140 is divided between Angad, Nick &amp; June so that Angad gets twice as much as Nick, and Nick gets three times as much as Ju
kramer

Answer:

84

Step-by-step explanation:

Let's say Nick gets amount N, Angad amount A, and June amount J.

Here's what we know:

A+N+J=140

A=2*N

N=3*J.

Let's plug these values in.

N=3*J, so A+N+J=140 can now be A+3*J+J=140.

A=2*N, and N=3*J, so A=2*3*J=6*J. Then, A+3*J+J=140 is now 6*J+3*J+J=140, so 10*J=140 and J=14. N = 3*J=42 and A=2*N=84. Checking this, 14+42+84=140, so we are good to go!

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3 years ago
I need help on a equation −4a5⋅6a5​
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3 years ago
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Sorry this is a tricky one IDK I'll ask some others to help you
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