Question

A can of tuna fish is a cylinder with a height of 1.75 inches and a diameter of 3 inches. If the can is half full, how many cubic inches of tuna is in the can?

Answer 1

Answer:

Step-by-step explanation:

jaz its alexis

Answer 2

Answer: $6.185in^3$

Step-by-step explanation:

The formula for calculate the volume of a cylinder is:

$V_{cylinder}=\pi r^2h$

r is the radius of the cylinder and h is the height of the cylinder.

Given the diameter of 3 inches, calculate the radius of the cylinder with:

$r=\frac{d}{2}$ (Where d is the diameter)

 $r=\frac{3in}{2}=1.5in$

Knowing the height and the radius, you can calculate the volume of the entire can of tuna:

$V_{can}=\pi (1.5)^2(1.75in)=12.37in^3$

As you want to know the cubic inches of tuna that are in the can (volume of tuna), and you know that the can is half full, then:

$V_{tuna}=\frac{V_{can}}{2}\\\\V_{tuna}=\frac{12.37in^3}{2}\\\\V_{tuna}=6.185in^3$