For every value tht x increases, y decreases by 3
-3x
Then to find the y intercept, look at 0's corresponding value (8)
-3x+8
Answer: You could move Circle 2 10 units to the right and up 5 up.
Doing this would put the centers of the circles at the same location. They would both be at the point (8, 5).
For the dilation, the radius changed from 2 to 6. Solve the following equation.
2x = 6
x = 3
Answer:
Binomial
There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.
Step-by-step explanation:
For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.
Binomial probability distribution:
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
In this problem
Of the 20 copies, 2 are defective, so
.
What is the probability that you will encounter neither of the defective copies among the 10 you examine?
This is P(X = 0) when
.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B10%2C0%7D.%280.1%29%5E%7B0%7D.%280.9%29%5E%7B10%7D%20%3D%200.3487)
There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.
The range is 0 to indifinity