Literally whatever number is in the parenthesis, if it’s negative like -4 then you could down 4 lines of squares and put a dot. if it’s positive then go up
14.75 depending on if the model is 8 & the actual is 1 in the 1:8 scale factor because you would just multiply the actual by 8 because it is the scale factor. the answer could also be .23 is the model is 1 & the actual is 8 because you would divide the actual by 8! hope this helps!!
Given : Diameter of the right circular cone ==> 8 cm
It means : The Radius of the right circular cone is 4 cm (as Radius is half of the Diameter)
Given : Volume of the right circular cone ==> 48π cm³
We know that :
![\bigstar \ \ \boxed{\textsf{Volume of a right circular cone is given by : $\pi r^2\dfrac{h}{3}$}}](https://tex.z-dn.net/?f=%5Cbigstar%20%5C%20%5C%20%5Cboxed%7B%5Ctextsf%7BVolume%20of%20a%20right%20circular%20cone%20is%20given%20by%20%3A%20%24%5Cpi%20r%5E2%5Cdfrac%7Bh%7D%7B3%7D%24%7D%7D)
where : r is the radius of the circular cross-section.
h is the height of the right circular cone.
Substituting the respective values in the formula, we get :
![\mathsf{\implies \pi \times (4)^2 \times \dfrac{h}{3} = 48\pi}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cimplies%20%5Cpi%20%5Ctimes%20%284%29%5E2%20%5Ctimes%20%5Cdfrac%7Bh%7D%7B3%7D%20%3D%2048%5Cpi%7D)
![\mathsf{\implies 16 \times \dfrac{h}{3} = 48}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cimplies%2016%20%5Ctimes%20%5Cdfrac%7Bh%7D%7B3%7D%20%3D%2048%7D)
![\mathsf{\implies \dfrac{h}{3} = 3}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cimplies%20%5Cdfrac%7Bh%7D%7B3%7D%20%3D%203%7D)
![\implies \boxed{\mathsf{h= 9 \ cm}}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cboxed%7B%5Cmathsf%7Bh%3D%209%20%5C%20cm%7D%7D)
<u>Answer</u> : Height of the given right circular cone is 9 cm
Answer: Choice D) x can be anything but 13
========================================================
Explanation:
The domain of
is the same as the domain of g(x)
The domain for g(x) is
saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because
![f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%2B7%5C%5C%5C%5C%5C%5Cf%28g%28x%29%29%20%3D%20g%28x%29%2B7%5C%5C%5C%5C%5C%5Cf%28g%28x%29%29%20%3D%20%5Cfrac%7B1%7D%7Bx-13%7D%2B7%5C%5C%5C%5C%5C%5C%28f%20%5Ccirc%20g%29%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx-13%7D%2B7%5C%5C%5C%5C%5C%5C)
and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.